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aniked [119]
3 years ago
15

One pump can fill a reservoir in 60 hours. Another pump can fill the same reservoir in 80 hours. a third can empty the reservoir

in 90 hours. If all three pumps are operating at the same time, how long will it take to fill the reservoir?
Mathematics
2 answers:
steposvetlana [31]3 years ago
7 0

one pump, let's call it A, fills the reservoir by 1/60 every hour. Now, B fills it by 1/80 every hour. C empties it by 1/90 every hour. All three are on, so now we combine them into one function: t(1/60 + 1/80 - 1/90) = 1, where t = the time it takes to fill it, and 1 is just our "reservoir finally filled" marker.

isolate t onto one side and we see t = 720/13 exactly, or approximately 55.38 hours. let me know if this is the wrong answer but I'm pretty sure it is correct!

11111nata11111 [884]3 years ago
4 0

Answer:

1/time needed = 1/time of 1st pump + 1/time of 2nd pump - 1/time of 3rd pump

1/t = 1/t1 + 1/t2 - 1/t3

1/t = 1/60 + 1/80 - 1/90

1/t = 12/720 + 9/720 - 8/720

1/t = 13/720

t = 720/13 hours = 55.38 hours = 55 hours 23 minutes

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Answer the precalculus question from khan academy pls! I will give brainliest and 5 stars. 30 points.
rosijanka [135]

The value of f(h(2)) =2 and h(f(16))= 14

<h3>What is function?</h3>

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input . Mapping or transformation is used to denote a function in math. These functions are usually denoted by letters . The domain is defined as the set of all the values that the function can input while it can be defined. The range is all the values that come out as the output of the function involved.

given:

f(x)= √x-1 , h(x)= x² + 5

Now,

f(h(2))= f( (2)² +5 )

=f(4+5)

=f(9)

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h(f(16)) = h( √16-1)

=h( 4-1)

=h(3)

=3² + 5

=9+5

=14

Learn more about function here:

brainly.com/question/12431044

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