Answer: y = -10 sin (πx) + 4
<u>Step-by-step explanation:</u>
y = A sin (Bx - C) + D
- Amplitude: A
- Period = 2π/B ---> B = 2π/Period
- Phase Shift = C/B --> C = B · Phase Shift
- D: midline, vertical shift
Given:
- A = 10
- B = 2π/2 = π
- C = B · 0 = 0
- D = 4
- reflection over x- axis
Equation:
y = -10 sin (πx - 0) + 4
Answer:
here
Step-by-step explanation:
15x-20x= -82+12=>
=> - 5x= -70=>
= x= 14
In an arithmetic sequence:
Tn=t₁+(n-1)d
t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d
t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d
Therefore:
3t₁+12d=300 (1)
t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d
t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d
Therefore:
3t₁+45d=201 (2)
With the equations (1) and (2) we make an system of equations:
3t₁+12d=300
3t₁+45d=201
we can solve this system of equations by reduction method.
3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
-33d=99 ⇒d=99/-33=-3
3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112
Threfore:
Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n
Now, we calculate T₁₈:
T₁₈=115-3(18)=115-54=61
Answer: T₁₈=61
Answer:
52.94
Step-by-step explanation:
61.06
-46.92
=52.94
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Answer:
8/5
Step-by-step explanation:
(y2-y1) / (x2-x1)
10-2 = 8
8-3 = 5
8/5
