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tamaranim1 [39]
3 years ago
9

What is the probability that a point chosen at random on the grid will lie in the shaded region?

Mathematics
1 answer:
Mashcka [7]3 years ago
8 0

Given:

A grid with a shaded region.

To find:

The probability that a point chosen at random on the grid will lie in the shaded region.

Solution:

We have,

Total number of small boxes = 100

Number of blue boxes (shaded region) = 36

Now,

probability that a point chosen at random on the grid will lie in the shaded region is

\text{Probability}=\dfrac{\text{Number of blue boxes (shaded region)}}{\text{Total number of small boxes}}

\text{Probability}=\dfrac{36}{100}

To find the probability in percent, multiply it by 100.

\text{Probability}\%=\dfrac{36}{100}\times 100

\text{Probability}\%=36\%

Therefore, the correct option is A.

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Answer:

<h2>The right option is twelve-fifths</h2>

Step-by-step explanation:

Given a right angle triangle ABC as shown in the diagram. If ∠BCA = 90°, the hypotenuse AB = 26, AC = 10 and BC = 24.

Using the SOH, CAH, TOA trigonometry identity, SInce we are to find tanA, we will use TOA. According to TOA;

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