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katen-ka-za [31]
3 years ago
14

How to convert mkv to avi without losing quality?

Computers and Technology
1 answer:
Alexus [3.1K]3 years ago
7 0
Ive done this before with success.
You will need <span>FFmpeg.</span>
https://superuser.com/questions/227338/how-to-convert-an-mkv-to-avi-with-minimal-loss
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Implement the following logic in C++, Use appropriate data types. Data types are represented as either numeric (num) or string.
ICE Princess25 [194]

Answer:

Follows are the modified code in c++ language:

#include<iostream>//header file

#include<string>//header file

using namespace std;

int main()//main method

{

string name,address, MSG_YES, MSG_NO;//defining string variable

int item,quantity,size=6, i=0;//defining integer variable

double price;//defining double variable  

int VALID_ITEM[]={106,108,307,405,457,688};//defining integer array and assign value

double VALID_ITEM_PRICE[]={0.59,0.99,4.50,15.99,17.50,39.00};//defining double array and assign value

bool foundIt=false;//defining bool variable  

MSG_YES="Item available";//use string variable to assign value

MSG_NO = "Item not found"; //use string variable to assign value

cout<<"Input name: ";//print message

cin>>name;//input value in string variable

cout<<"Input Address: ";//print message

cin>>address;//input value in string variable

cout<<"Input Item: "<<endl;//print message

cin>>item;//input value in string variable

cout<<"Input Quantity: "<<endl;//print message

cin>>quantity;//input value in string variable

while(i <size)//defining while that checks i less then size  

{

if (item ==VALID_ITEM[i]) //use if block to match item in double array

{

foundIt = true;//change bool variable value

price = VALID_ITEM_PRICE[i];//hold item price value in price variable  

}

i++;//increment the value of i

}

if (foundIt == true)//use if to check bool variable value equal to true

{

cout<<MSG_YES<<endl;//print value

cout<<"Quantity "<<quantity<<" at "<<"Price "<<price<<"each"<<endl;//print value

cout<<"Total"<<quantity*price;//calculate the total value

}

else//else block

cout<<MSG_NO;//print message  

}

Output:

please find the attached file.

Explanation:

In the above given C++ language modified code, four-string variable " name, address, MSG_YES, and MSG_NO", four integer variable "item, quantity, size, and i", and "integer and double" array is defined, that holds values.

In the string and integer variable "name, address, and item, quantity", we input value from the user-end and use the while loop, which uses the if block to check the "item and quantity" value from the user end and print its respective value.

6 0
4 years ago
What is thought to have caused the extinction of the dinosaurs?
AnnyKZ [126]
I think it's believed that an asteroid that hit Earth caused their extinction.
3 0
4 years ago
The repair order is a legal document because?
svp [43]
D. It’s signed by the customer
4 0
3 years ago
Read 2 more answers
2. Write these functions definitions:
GREYUIT [131]

Answer:

Complete the code with the following code segment:

void add2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

   cout<<num1+num2;

}

void sub2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

   cout<<num1-num2;

}

void mul2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

   cout<<num1*num2;

}

void div2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

if(num2==0){

cout<<"Division by 0 is invalid";

}else{

   cout<<(float)num1/num2;}

}

Explanation:

The function added to this solution are:

  • add2Numbers
  • sub2Numbers
  • mul2Numbers
  • div2Numbers

Each of the functions

  • declares two integers num1 and num2
  • prompt user for inputs
  • gets user inputs from the user

For add2Numbers() function:

This line adds the two integer numbers and prints the result

   cout<<num1+num2;

For sub2Numbers() function:

This line subtracts the two integer numbers and prints the result

   cout<<num1-num2;

For mul2Numbers() function:

This line multiplies the two integer numbers and prints the result

   cout<<num1*num2;

For div2Numbers() function:

This if condtion checks if the denominator is 0

if(num2==0){

If yes, the following is printed

cout<<"Division by 0 is invalid";

If otherwise, the division is calculated and the result is printed

   cout<<(float)num1/num2;

<em>See attachment for complete program</em>

Download cpp
7 0
3 years ago
Write a program in c language to generate following series :
DedPeter [7]

In this exercise we have to have knowledge in computational language in C to write the requested code.

The code is found in the attached image.

We can write the code in a simpler way like:

<em>#include<stdio.h></em>

<em>#include<conio.h></em>

<em>int main()</em>

<em>{</em>

<em>    int N, i;</em>

<em>    printf("Enter the value of N (limit): ");</em>

<em>    scanf("%d", &N);</em>

<em>    printf("\n");</em>

<em>    for(i=1; i<=N; i++)</em>

<em>    {</em>

<em>        if(i==N)</em>

<em>            printf("%d", i);</em>

<em>        else</em>

<em>            printf("%d,", i);</em>

<em>    }</em>

<em>    getch();</em>

<em>    return 0;</em>

<em>}</em>

See more about C language at brainly.com/question/19705654

7 0
3 years ago
Read 2 more answers
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