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2 years ago

The technique that allows you to have multiple logical lans operating on the same physical equipment is known as a.

Computers and Technology

1 answer:

sergiy2304 [10]2 years ago

5 0

Answer:

As far as i know, it is Virtual Local Area Network (VLAN). You can read more about this here: https://en.wikipedia.org/wiki/VLAN

You might be interested in

Write a function NumberOfPennies() that returns the total number of pennies given a number of dollars and (optionally) a number

Over [174]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int NumberOfPennies(int ND, int NP=0)//defining a method that accepts two parameters

{

return (ND*100 +NP);//use return keyword that fist multiply by 100 then add the value

}

int main() //main method

{

cout << NumberOfPennies(5,6) << endl; // Should print 506

cout << NumberOfPennies(4) << endl; // Should print 400

return 0;

}

Output:

506

400

Explanation:

In the method "NumberOfPennies" it accepts two parameters that are "ND and NP" that uses the return keyword that multiply 100 in ND variable and add in NP variable and return its values.

In the main method it it uses the cout method that call the by accepts value in parameter and print its value.

4 0

3 years ago

Consider the following code segment.

mafiozo [28]

Answer:

for (int h = k; h >= 0; h--)

Explanation:

From the list of given options, option C answers the question.

In the outer loop

Initially, k = 0

In the inner loop,

h = k = 0

The value of h will be printed once because h>=0 means 0>=0 and this implies once

To the outer loop

k = 1

The inner loop will always assume value of k;

So,

h = 1

This will be printed twice because of the condition h>=0 means 1>=0.

Since 1 and 0 are >=0; 1 will be printed twice

To the outer loop

k = 2

The inner loop

h = 2

This will be printed thrice because of the condition h>=0 means 2>=0.

Since 2, 1 and 0 are >=0; 2 will be printed thrice

To the outer loop

k = 3

The inner loop

h = 3

This will be printed four times because of the condition h>=0 means 3>=0.

Since 3, 2, 1 and 0 are >=0; 3 will be printed four times

7 0

3 years ago

Jack was drinking a glass of water near his computer when his dog bumped his arm, spilling water on his keyboard. What is the fi

Anvisha [2.4K]

Answer:

4no. is the answer may be

3 0

2 years ago

Read 2 more answers

Historia da inteligencia artificial

choli [55]

Answer:

hshdhwvevwuwijwvww

Explanation:

wwgwvisgwgqiwieoiw

5 0

2 years ago

Read 2 more answers

Given parameters b and h which stand for the base and the height of an isosceles triangle (i.e., a triangle that has two equal s

schepotkina [342]

Answer:

The area of the triangle is calculated as thus:

$Area = 0.5 * b * h$

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

$s = \sqrt{b^2 + h^2}$

The perimeter of the triangle is then calculated as thus;

$Perimeter = s + s + b$

$Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b$

$Perimeter = 2\sqrt{b^2 + h^2} + b$

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

$Volume = \frac{1}{3} \pi * r^2 * h$

Where $r = \frac{1}{2} * diameter$

So, $r = \frac{1}{2}b$

So, $Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h$

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

return 0;

}

3 0

2 years ago