There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
![_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\ =1140](https://tex.z-dn.net/?f=_%7B20%7D%20C%20_3%3D%5Cfrac%7B20%21%7D%7B3%21%2820-3%29%21%7D%3D%5Cfrac%7B20%21%7D%7B3%21%20%5Ctimes%2017%21%7D%3D%5Cfrac%7B17%21%20%5Ctimes%2018%20%5Ctimes%2019%20%5Ctimes%2020%7D%7B6%20%5Ctimes%2017%21%7D%3D%5Cfrac%7B18%20%5Ctimes%2019%20%5Ctimes%2020%7D%7B6%7D%3D3%20%5Ctimes%2019%20%5Ctimes%2020%3D%20%5C%5C%0A%3D1140)
There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
![_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20](https://tex.z-dn.net/?f=_6%20C%20_3%20%3D%20%5Cfrac%7B6%21%7D%7B3%21%286-3%29%21%7D%3D%5Cfrac%7B6%21%7D%7B3%21%20%5Ctimes%203%21%7D%3D%5Cfrac%7B3%21%20%5Ctimes%204%20%5Ctimes%205%20%5Ctimes%206%7D%7B3%21%20%5Ctimes%206%7D%3D%5Cfrac%7B4%20%5Ctimes%205%20%5Ctimes%206%7D%7B6%7D%3D4%20%5Ctimes%205%3D20)
The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
![P= \frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}](https://tex.z-dn.net/?f=P%3D%0A%5Cfrac%7B20%7D%7B1140%7D%3D%5Cfrac%7B20%20%5Cdiv%2020%7D%7B1140%20%5Cdiv%2020%7D%3D%5Cfrac%7B1%7D%7B57%7D)
The probability is 1/57.
Answer: 1-91,1-42,101,161
Answer:
83.8 cm
Step-by-step explanation:
Multiply it then you’ll get your answer
Answer:eu noa
Step-by-step explanation:falo inglês