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aivan3 [116]
3 years ago
13

what is the point-slope form of the equation of the line passing through the points (–6, –4) and (2, –5).

Mathematics
1 answer:
ioda3 years ago
7 0

Answer:

The equation of the line would be y + 4 = -1/8(x + 6)

Step-by-step explanation:

To find the point-slope form of the line, start by finding the slope. You can do this using the slope formula below along with the two points.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-4 - -5)/(-6 - 2)

m = 1/-8

m = -1/8

Now that we have the slope, we can use that along with one of the points in the base form of point-slope.

y - y1 = m(x - x1)

y + 4 = -1/8(x + 6)

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Can anyone figure this out for me please? It would be greatly appreciated.
Ira Lisetskai [31]
Check the picture below.

now, to get how much is the area of the tiled section, we simply get the area of the whole pool, 53x26, which includes the tiles, and then subtract the area without the tile, the rectangle in the middle, and what's leftover, is the area of the tiled area.

\bf 53-4\frac{1}{2}-4\frac{1}{2}\implies 53-9\implies \boxed{42}
\\\\\\
26-4\frac{1}{2}-4\frac{1}{2}\implies 26-9\implies \boxed{17}
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\textit{so the area of the rectangle in the middle is}\implies 42\cdot 17\implies 714
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\textit{and the area of the whole pool is}\implies 53\cdot 26\implies 1378

\bf \stackrel{\textit{area of the whole pool}}{1378}~~-~~\stackrel{\textit{area of the middle rectangle}}{714}\implies \stackrel{\textit{area of the tiles}}{664}\\\\
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\textit{we know that is }\$5\frac{1}{2}\textit{ for a foot of tile, then}\stackrel{\textit{price of the tiles}}{664\cdot 5\frac{1}{2}}\implies 3652

8 0
3 years ago
At 3pm the temperature was 9 degrees .By 11pm ,it had dropped 31 degrees .What was the temperature at 11pm
o-na [289]

Answer:

-22

Step-by-step explanation:

9-31=-22

5 0
2 years ago
5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?​
Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0
2 years ago
The quadratic function: <img src="https://tex.z-dn.net/?f=y%3D-x%5E2-8x%2B1" id="TexFormula1" title="y=-x^2-8x+1" alt="y=-x^2-8x
pav-90 [236]

Answer:

  2)  (-∞, 17]

Step-by-step explanation:

The leading coefficient of the function is negative, so the parabola opens downward. The vertex will be a maximum, the upper end of the range. The lower end of the range will be -∞.

The vertex of the function lies on the axis of symmetry. The maximum can be found by evaluating the function at x=-4.

  y = -(-4)² -8(-4) +1 = -16 +32 +1 = 17

The range of the function is (-∞, 17].

8 0
1 year ago
Where are the minimum and maximum values for f(x) = -2 + 4 cos x on the interval (0,21]?
Dafna11 [192]

Answer:

Step-by-step explanation:

Maximum value is when cos x = 1

So it is -2 + 4(1) = 2.

Minimum value, when  cos x = -1:

= -2  + 4(-1) = -6.

4 0
3 years ago
Read 2 more answers
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