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162/(6(7-4)^2)
pemdas
parenthasees inner first
so 7-4 is forst
7-4=3
162/(6(3)^2)
then exponents
3^2=9
162/(6(9))
multiplication
6 times 9=54
162/(54)=3
Look at it this way:
g=2
H=7
so it would be 2*5-7*3
than just do the multiplication first so 2*5=10 and 7*3=21 than subtract the two 10-21=-11
Answer:
it goes up (x) goes by 5 and (y) by 7
Step-by-step explanation:
