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trapecia [35]
3 years ago
6

Find the domain of: F(x)= x^2-4/2x^3-32x

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
6 0
The domain of the equation is infinity.
nikklg [1K]3 years ago
4 0
Hello : 
<span>F(x)= x^2-4/2x^3-32x
F exist if : </span>2x^3-32x <span>≠ 0
</span>2x^3-32x = 0
2x (x²-16)=0
2x(x-4)(x+4)=0
2x=0 or x-4=0 or x+4 =0
x=0 or x=4 or x= -4
the domain is : D= ] -∞ <span>; -4[ </span> ∪ ] -4 ; 0[∪ ] 0 ; 4[ ∪ <span>]4 ; + ∞[<span> </span></span>
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X+ y + z = -3<br> 3y - Z = 4<br> 2x- y - 2z = -5
snow_lady [41]

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Step-by-step explanation:

  • x + y + z = -3  --> (1)
  • 3y - z = 4   --> (2)
  • 2x - y - 2z = -5 --> (3)

<u>Add up (1) and (2)</u>

  • x + 3y + y + z - z = -3 + 4 ⇒ x + 4y = 1  --> (4)

<u>Double (2) and subtract from (3)</u>

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<u>Double (4) and subtract (5)</u>

  • 2(x + 4y) - 2x + 7y = 2 + 13 ⇒ 2x + 8y - 2x + 7y = 15 ⇒ 15y = 15 ⇒ y = 1

<u>Finding x</u>

  • x + 4(1) = 1 ⇒ x = 1 - 4  ⇒ x = -3

<u>Finding z</u>

  • -3 + 1 + z = -3 ⇒ z = -1

<u>So the answer is: </u>

  • (-3, 1, -1)

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3 years ago
What is the area of a circle with a radius of 13 millimeters? <br> (Use 3.14 for Pi.)
ludmilkaskok [199]
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