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telo118 [61]
4 years ago
6

Use the Law of Sines to solve the triangle. Round your answers to two decimal places.

Computers and Technology
1 answer:
iris [78.8K]4 years ago
5 0

Answer: 37.1

Explanation: The Law of sines states that there is a proportionality between a side of triangle and its correspondent angle, i.e.:

\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}

where:

a, b and c are sides

A, B and C are angles

In the question, there is a triangle with 27.4 as a measure of side a, angles A and C. So, it wants the side c:

\frac{a}{sinA} = \frac{c}{sinC}

\frac{27.4}{sin(99.7)} = \frac{c}{sin(20.4)}

c = \frac{27.4.sin(20.4)}{sin(99.7)}

c = 37.1

The side c is 37.1

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Middleware is the solution to conflicting software applications, interconnectivity between various tech platforms. It promotes cross-platform interactions.

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a password to a certain database consists of digits that cannot be repeated. if the password is known to consist of at least 8 d
BaLLatris [955]

Answer:

\frac{10!}{2}mins

Explanation:

12 seconds to try one combination will be equivalent to  \frac{1}{12}\times 60 = \frac{1}{5} \ mins

Password contain at least 8 digit i.e. password can contain 8, 9, 10 digit.

Password cannot contain more than 10 digit because it will give room for repetition which it is clearly stated that digit cannot be repeated.

Possible digit that can be used: 9,8,7,6,5,4,3,2,1,0.

Total number of passwords combination possible for each position in 8 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3. Total number of passwords combination possible in 8 digit is equivalent to \frac{10!}{2}.

Total number of passwords combination possible for each position in 9 digit.  

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2. Total number of passwords combination possible in 9 digit is equivalent to \frac{10!}{1}.

Total number of passwords combination possible for each position in 10 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2, 10th position = 1.  Total number of passwords combination possible in 10 digit is equivalent to 10!.

Adding them up and multiplying by  \frac{1}{5} \ mins  to get the total number of time needed to guarantee access to database =  [\frac{10!}{2}\times\ \frac{10!}{1} \times 10!] \frac{1}{5}\ mins = \frac{10!}{2}

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3 years ago
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