Answer:
Lol .... I don't know the answer :D :P
Step-by-step explanation:
L.H.S x 0 = 0
R.H.S x 0 = 0
L.H.S = R.H.S
Hence , proved .....
A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.
b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.
c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.
d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.
.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
Answer: It's either -6 or 12. I'm assuming it's 12 because it says "more than."
Step-by-step explanation:
6,000.000+800.000+50.000+8.000+0.000+0.20+0.6
Answer:
530.66 mm²
5.3066 cm²
Step-by-step explanation:
A = π·r²
= 3.14×(13mm)²
= 3.14×169mm²
= 530.66 mm²
= 5.3066 cm²
