Ok, I'm only in 8th grade but I believe you do addition first in the problem. Hope this helps! <3
Answer:
Step-by-step explanation:
We assume that there are 100 sour candies, Thus-
26 % of candy are grape implies that 26% of 100 candies are grape that is equal to 26
Now remaing candies that are not grape are 100-26 = 74
Based on the rule of multiplication:
P(A ∩ B) = P(A)/ P(B|A)
In the beginning, there are 26grape candies, probability of choosing first grape candy = 26C1 = 26
After the first selection, we replace the selected grape candy so there are still 100 candies in the bag P(B|A) = 100C3 = 100 x 99 x 98 x 97!/3! X 97!
= 50 x 33 x 98
So probability =1/ 50 x 33 x 98 x 26
= 1/4204200
I think it is 21 and 50. The only common factor they have is 1.
All the others are divisible by 1 & 3.
Answer:
See explanation
Step-by-step explanation:
Let
be the number of students and
be the number of adults on the show.
1. Tickets cost $15 for students, so x student tickets cost $15x.
Tickets cost $25 for adults, so y adult tickets cost $25y.
Total cost of all tickets is $(15x + 25y).
The charity show is conducted in order to raise at least $3,750, thus

2. The auditorium can accommodate up to 180 spectators, hence

3. We get the system of inequalities:

Plot all solutions sets to each inequality and the common region is the solution set to the system of inequalities. This region is not empty, so the charity will reach its goal. For example, if they sell 50 students tickets and 125 adult tickets, they will raise 
Answer: concave
Step-by-step explanation: