Opposite sides of a parallelogram are equal lengths, so ...
... AB = CD
... 6x +30 = 2y -10
and
... BC = AD
... 2x -5 = y -35
_____
The equations can be put in standard form to get
... 3x -y = -20
... 2x -y = -30
Subtracting the second from the first, we get
... x = 10
Solving for y, we have
... y = 2x+30 = 2·10 +30 = 50
The values of x and y are x=10, y=50.
_____
AB = 6x+30 = 90
BC = 2x-5 = 15
Hello :
q(r)=3<span>√(r²-16)
q exist : r² - 16 </span><span>≥ 0
r² </span><span>≥ 16
</span>√r² ≥ √16
but : √16 = 4 and √r² = <span>|r
|
</span>|r | ≥ 4
r ≤ 4 or r ≥ 4
the domain is : ] -∞, 4] ∪ [,4 , +
∞ [
Answer:
12x+25y is greater then or equalt to 250
Step-by-step explanation:
I think the answer would 28