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Andru [333]
1 year ago
15

What is the area of the sector a.) 10π cm^2b.) 16π cm^2c.) 40π cm^2d.) 64π cm^2

Mathematics
1 answer:
Natalija [7]1 year ago
3 0

Answer:

C. 40π cm²

Explanation:

• The central angle of the sector = 225 degrees

,

• The radius of the sector = 8cm

For a sector of radius r and central angle θ, we calculate the area using the formula below:

\text{Area}=\frac{\theta}{360\degree}\times\pi r^2

Substituting the given values, we have:

\begin{gathered} \text{Area}=\frac{225}{360}\times\pi\times8^2 \\ =\frac{5}{8}\times64\times\pi \\ =5\times8\times\pi \\ =40\pi cm^2 \end{gathered}

The area of the sector is 40π cm².

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The accompanying data represent the daily​ (for example, Monday to​ Tuesday) movement of Johnson​ & Johnson​ (JNJ) stock for
egoroff_w [7]

Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

  • The lower bound is of 0.484.
  • The upper bound is of 0.7292.
  • The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

Supposing that it increases on 37 out of 61 days:

n = 61, \pi = \frac{37}{61} = 0.6066

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

The ​95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

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2 years ago
S а о -3 S - 14 2 -S # -3 -2 1+ A + Lovezujo edos e seu molaguude 16 avuq UUDIUM​
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Answer:

Line Q is the line with the slope of 0.

Step-by-step explanation:

It does not increase or decrease.

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2 years ago
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Answer:

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3 years ago
How do I find each measure? Please I need answers ASAP it's due at 1:50
Norma-Jean [14]

Answer:

Angle CAD is 44 degrees

Angle ACD is 44 degrees

Angle ACB is 136 degrees

Angle ABC is 22 degrees

Explanation:

29. Triangle ADC is an isosceles triangle because it has two equal sides.

If segments AD and DC are congruent, then segment AC is the base and the base angles of an isosceles triangle are equal.

Let x be angle CAD.

Let's go ahead x;

\begin{gathered} 92+x+x=180\text{ (sum of angles in a triangle)} \\ 92+2x=180 \\ 2x=180-92 \\ 2x=88 \\ x=\frac{88}{2} \\ \therefore x=44^{\circ} \end{gathered}

Therefore, measure of angle CAD is 44 degrees.

30. Measure of angle ACD is 44 degrees (Base angles of an isosceles triangle are equal)

31. Let angle ACB be y,

Let's go ahead and find measure of angle ACB;

\begin{gathered} 44+y=180\text{     (angles on a straight line)} \\ y=180-44 \\ \therefore y=136^{\circ} \end{gathered}

So measure of angle ACB is 136 degrees.

32. Let angle ABC be z.

Triangle ACB is also an isosceles triangle so the base angles are the same.

Let's go ahead and find z;

\begin{gathered} 136+z+z=180_{}\text{    (sum of angles in a triangle)} \\ 138+2z=180 \\ 2z=180-136 \\ 2z=44 \\ z=\frac{44}{2} \\ \therefore z=22^{\circ} \end{gathered}

So measure of angle ABC is 22 degrees.

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{(-1, 2), (0, 2), (5, 2)} is a function.
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The relation is a function.

Step-by-step explanation:

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