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Rudik [331]
2 years ago
10

Factor mn - 15 + 3m - 5n

Mathematics
1 answer:
AfilCa [17]2 years ago
8 0
(n+3)(m-5) is the answer.
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Helppppp please will give brainlist ​
NeX [460]

Answer:

D or answer 4                   y=-5/2x+7

Step-by-step explanation:

Well we can first start of by finding the y-intercept.

Note that when x=0, you can find your y-intercept.

Knowing this, and looking at the table, 7 is the y-intercept because when y=7, x=0.

So we can eliminate choices 'a' and 'c,' or answers 1 and 3, because they have the y-intercept as -7, when it's just 7.

Please know that in the equation:

y = mx + b

y = y-coordinate or any given point

mx = slope

b = y-intercept

Now we must find slope

To find the slope we need to do:

(y2 - y1) / (x2 - x1) or rise/run

The two coordinates I choose to use is (0, 7) and (6, -8).

(-8 - 7) / (6 - 0) = -5/2

-5/2 is the slope

Finally, look for an equation that has 7 as the y-intercept and -5/2 as the slope.

Answer: D or answer 4

7 0
3 years ago
Can u pls help me with this
BabaBlast [244]

Answer:

Problem 1:

x=12, x=3, x=6

Problem 2:

18*3=54

54/18=3

Problem 3:

Part A: 36/4.5=? 4.5*x=36

Part B: 8

Step-by-step explanation:

7 0
2 years ago
Write an equivalent exponential expression for “five to the third power. " Evaluate the expression.
Likurg_2 [28]
5^{3}   is the equivalent to "five to the third power"
4 0
3 years ago
Read 2 more answers
(Click the Picture for my question) and thank you!
ELEN [110]
The answer should be C
7 0
3 years ago
Read 2 more answers
It is desired to pile some logs in layers so that the top layer contains one log, the next layer contains two logs, the next lay
Hitman42 [59]

Answer:

Yes all of the logs can be used in such a grouping.

We'll have <u>19 logs</u> in the bottom row (and have 19 rows)

========================================================

Explanation:

Let n be the number of layers. Let T(n) represent how many logs there are total.

  • If you have 1 layer, then you have 1 log. So we can say that T(1) = 1.
  • If there are n = 2 layers, then we have 1 log on top of two other logs, which leads to 1+2 = 3 logs total. This shows that T(2) = 3.
  • If there are n = 3 layers, then we have 1 log on top of 2 which are on top of 3 at the very bottom. We have 1+2+3 = 6 logs total. So T(3) = 6.
  • Having n = 4 layers gives 1+2+3+4 = 10 logs. So T(4) = 10
  • Having n = 5 layers gives 1+2+3+4+5 = 15 logs. So T(5) = 15

This process continues for however long you like. The sequence 1,3,6,10,15 is the set of triangular numbers, since the logs form a triangular or pyramid shape when stacked this way. To get the nth value in the triangular number sequence, use this formula

T(n) = 0.5*n*(n+1)

---------------

For example, let's say we wanted to find how many logs there were in the fifth layer

T(n) = 0.5*n*(n+1)

T(5) = 0.5*5*(5+1)

T(5) = 15

This matches from earlier.

The purpose of bringing in a formula is to see if we can get T(n) = 190 for some integer n.

-------------------

T(n) = 0.5*n*(n+1)

190 = 0.5*n*(n+1)

190*2 = n(n+1)

380 = n^2+n

0 = n^2+n-380

n^2+n-180 = 0

Applying the quadratic formula will lead to the two solutions: n = -20 and n = 19. We ignore the negative value of n as we can't have a negative number of rows. Therefore, n = 19 is the only valid solution here.

If we wanted to stack 190 logs in this triangular pyramid fashion, then we'll need to have 19 rows. The bottom row will have 19 logs.

----------

Check:

1+2+3+4+5+6+7+8+9+10 = 55

11+12+13+14+15+16+17+18+19 = 135

55+135 = 190

Or you could say,

T(n) = 0.5*n*(n+1)

T(19) = 0.5*19*(19+1)

T(19) = 190

Either way, the answer is confirmed.

8 0
2 years ago
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