Answer:
a
Step-by-step explanation:
go it right on a mastery test
To solve this problem, we can set up an equation, letting the unknown value of last month's supply sales be represented by the variable x.
First, we must convert 78% to its decimal equivalent, by dividing 78/100. This is because percentages are parts of a whole 100 percent.
78/100 = 0.78
Now, we are ready to set up our equation, using our knowledge that the word "of" refers to multiplication in mathematics.
3,285 = 0.78x
To solve our equation, we must divide both sides of the equation by 0.78 to get the variable x alone on the right side of the equation.
x = 4211.53846154
This means that last month's supply sales were about $4,211.54 (we round the last digit up because 8 is greater than 5).
Hope this helps!
Answer: the probability that a truck drives between 166 and 177 miles in a day is 0.0187
Step-by-step explanation:
Since mileage of trucks per day is distributed normally, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = mileage of truck
µ = mean mileage
σ = standard deviation
From the information given,
µ = 100 miles per day
σ = 37 miles miles per day
The probability that a truck drives between 166 and 177 miles in a day is expressed as
P(166 ≤ x ≤ 177)
For x = 166
z = (166 - 100)/37 = 1.78
Looking at the normal distribution table, the probability corresponding to the z score is 0.9625
For x = 177
z = (177 - 100)/37 = 2.08
Looking at the normal distribution table, the probability corresponding to the z score is 0.9812
Therefore,
P(166 ≤ x ≤ 177) = 0.9812 - 0.9625 = 0.0187
