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irakobra [83]
3 years ago
7

Y=5x Is it proportional or not ?

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0
Yes it is proportional.
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<img src="https://tex.z-dn.net/?f=%5C%7B%20%5Cfrac%20%7B%20%28%20%5Csqrt%20%7B%203%20%7D%20%29%20%5Ctimes%203%20%5E%20%7B%20-%20
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Step-by-step explanation:

Exponent law:

    \sf \bf a^m * a^n = a^{m+n}\\\\ (a^m)^n = a^{m*n}

    \sf a^{-m}=\dfrac{1}{a^m}

       First convert radical form to exponent form and then apply exponent law.

 \sf \sqrt{3}=3^{\frac{1}{2}}\\\\\sqrt{5}=5^{\frac{1}{2}}

\sf \left(\dfrac{(\sqrt{3}*3^{-2}}{(\sqrt{5})^2}\right)^{\frac{1}{2}}= \left(\dfrac{3^{\frac{1}{2}}*3^{-2}}{(5^{\frac{1}{2}})^2} \right )^{\frac{1}{2}}

                      = \left(\dfrac{3^{\frac{1}{2}-2}}{5^{\frac{1}{2}*2}}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{1-4}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{-3}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\dfrac{3^{\frac{-3}{2}*{\frac{1}{2}}}}{5^{\frac{1}{2}}}\\\\ =\dfrac{3^{{\frac{-3}{4}}}}{5^{\frac{1}{2}}}

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2 years ago
Find the shape of the area below.<br> Please thank you
xenn [34]

Answer:

i cant see the picture

Step-by-step explanation:

post it again

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