How do you calculate the angle of depression
2 answers:
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So this is trig, and when it comes to right (90°) triangles, it's imperative that you know:
SOH-CAH-TOA
Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent
*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles
therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:
Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or
it's basically a fancy function of most advanced calculators, so we'll plug it in as:
x = 33.49° --> answer B) is correct
SOH-CAH-TOA
Sine (x) = Opposite/Hypotenuse
Cosine (x) = Adjacent/Hypotenuse
Tangent (x) = Opposite/Adjacent
*hypotenuse is always the largest side, and the one opposite the 90° angle in right triangles
therefore we'll use SOH, because the opposite of x (O) and the hypotenuse (H) are given:
Sine (x) = Opposite/Hypotenuse
Sine (x) = 32/58 = 16/29 = 0.552
Sine (x) = 0.552
now we use something called arc-sine, or
it's basically a fancy function of most advanced calculators, so we'll plug it in as:
x = 33.49° --> answer B) is correct
Answer:
See below :)
Step-by-step explanation:
We know that these traingles are all similar. We can see the angle NMK is 60 degrees so we also know that JNK is 60 degrees. Now we know that all of the triangles are 30-60-90 triangles. JN is 3, so from the "leg opposite to 30 degree theorem", we know that NK is two times JN which is 6. Then from the same theorem, we know that NM is NK divided by the square root of 3
We can't have fractions that have irrational numbers in the denominator of a fraction so we multiply it by root3 over root3
*
This then makes it 6 times root 3 over 3
We then get