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beks73 [17]
3 years ago
15

Give an example of a nested sequence of open bounded intervals such that there is no point that belongs to all of the intervals

g
Mathematics
1 answer:
Damm [24]3 years ago
5 0


let n take values 1,2,3... infinity

then the sequence is:


(0,1/n)

for every number greater than zero there exist such n that (0,1/n) does not contain that number.
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2. What percent of rolling a 2<br><br><br> 3 probability of getting HH
faust18 [17]

<u>Answer:</u>

2. The correct answer option is 25%.

3. The experimental probability is 3% greater than the theoretical probability.

<u>Step-by-step explanation:</u>

2. We are given that a number cube is rolled 20 times out of which 5 times it lands on the number 2.

We are to find the experimental probability of getting the number 2.

P (2) = \frac{5}{20} \times 100 =\frac{1}{4} \times 100 = 25%

3. The theoretical Outcomes are: HH HT TH TT

So theoretical probability of getting HH = \frac{1}{4} \times 100 = 25%

Total number of outcomes = 28+22+34+16 = 100

So experimental probability of getting HH = \frac{28}{100} \times 100 = 28%

Therefore, the experimental probability is 3% greater than the theoretical probability.

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The Science Club has 35 members, 10 girls and 25 boys. What is the ratio of girls to boys in the Science Club?
lbvjy [14]
The answer is: B. 2:5
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3 years ago
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Bert uses a map to find his way around a state park. The map has a scale of 1 inch = 0.75 miles. He follows a path 6.75 miles fr
boyakko [2]

Answer:

9 inches

Step-by-step explanation:

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4 0
2 years ago
Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining
Flura [38]

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

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3 years ago
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