Answer: 25%
Step-by-step explanation:
Given : Previous baby's weight = 18 pounds
New baby's weight = 24 pounds.
Increase in weight = New weight -Previews weight
=24 pounds - 18 pounds =6 pounds
Percentage increase in baby's weight =

Hence, the percentage increase in baby's weight = 25%
Answer:
Rs 448
Step-by-step explanation:
400 × 1.12 = 448
this a 12 % increase
For this case we must find an expression equivalent to:

By definition of power properties we have to meet:

Then, we can rewrite the expression as:

Answer:

<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
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