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salantis [7]
4 years ago
9

Hello!) this is math :( Can you help me please?

Mathematics
1 answer:
Zarrin [17]4 years ago
6 0

The standard form: Ax + By = C.

The point-slope form:

y-y_1=m(x-x_1)

6. We have m =-2 and the point (-7, -10). Substitute:

y-(-10)=-2(x-(-7))\\\\y+10=-2(x+7)\qquad|\text{use distributive property}\\\\y+10=(-2)(x)+(-2)(7)\\\\y+10=-2x-14\qquad|-10\\\\y=-2x-24\qquad|+2x\\\\\boxed{2x+y=-24}

7. We have m = 4 and the point (-3, 0). Substitute:

y-0=4(x-(-3))\\\\y=4(x+3)\qquad|\text{use distributive property}\\\\y=(4)(x)+(4)(3)\\\\y=4x+12\qquad|-4x\\\\-4x+y=12\qquad|\text{change the signs}\\\\\boxed{4x-y=-12}


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4 years ago
Find the standard deviation. Round to the nearest tenth. 1, 2, 11, 8, 16, 16,20, 16, 18 OA. 6.5 O B. 6.9 O C. 1.5 ? D. 7.4
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Answer:

A. 6.5

Step-by-step explanation:

First we find the average  \bar{x} of the 9 data:

\bar{x} =\frac{\sum_{x=1}^{n}x_{i}}{n}

Where n is the data number, that in this case is 9.

\bar{x} =\frac{1+ 2+ 11+ 8+ 16+ 16+20+ 16+ 18}{9}=12\\

The formula of the standard deviation \sigma is:

\sigma=\sqrt{\frac{\sum_{x=1}^{n}(x_{i}-\bar{x})^{2}}{n}}

We replace the data and find the value of the standard deviation:

\sigma=\sqrt{\frac{(1-12)^{2}+(2-12)^{2}+(11-12)^{2}+(8-12)^{2}+(16-12)^{2}+(16-12)^{2}+(20-12)^{2}+(16-12)^{2}+(18-12)^{2}}{9}}

\sigma=\sqrt{\frac{(-11)^{2}+(-10)^{2}+(-1)^{2}+(-4)^{2}+(4)^{2}+(4)^{2}+(8)^{2}+(4)^{2}+(6)^{2}}{9}}=6,54

We approximate the number and the solution is 6,5

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After the first 15 hours, 450 g decays to half this amount, 225 g.

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After the next 15 (total 45), 112.5 g decays to 56.25 g.

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the difference of 5 times the cube of x cubed and the quotient of 4 times x and 3


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