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11Alexandr11 [23.1K]
3 years ago
12

What are the solutions of the equation (x + 2)2 + 12(x + 2) – 14 = 0? Use u substitution and the quadratic formula to solve. x =

negative 8 plus-or-minus 5 StartRoot 2 EndRoot x = negative 6 plus-or-minus 5 StartRoot 2 EndRoot x = negative 4 plus-or-minus 5 StartRoot 2 EndRoot x = negative 2 plus-or-minus 5 StartRoot 2 EndRoot
Mathematics
2 answers:
Maru [420]3 years ago
8 0

Answer:

B. x = -6 +/- 2\sqrt{5}

Step-by-step explanation:

substitute u for (x+2)

u^2+12u -14=0

use the quadratic formula

 \frac{-b plus-or-minus \sqrt{b^{2}- 4ac } }{2a}

\frac{-12 plus-or-minus \sqrt{200} }{2}

\frac{-12 plus-or-minus 10\sqrt{2} }{2}

Then set everything equal to u: (x+2)

u+2=\frac{-12 plus-or-minus 10\sqrt{2} }{2}

u-2= -12 plus-or-minus 10 sqrt{2}/2

nika2105 [10]3 years ago
4 0

Answer:

A:

Step-by-step explanation:

Edg 2020

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