Find the unknown side length, x. write your answer in simplest radical form.

Sophia and Charlie brought potato salad to the company cookout. Sophia brought 2 quarts and Charlie brought 4 pints. How many TO

yaroslaw [1]

16 cups of potato salad

3 0

4 years ago

What number x makes the equation 8 to the power of x = 2 correct?

Daniel [21]

A linear equation in one variable has a single unknown quantity called a variable represented by a letter. Eg: ‘x’, where ‘x’ is always to the power of 1. This means there is no ‘ x² ’ or ‘ x³ ’ in the equation.The process of finding out the variable value that makes the equation true is called ‘solving’ the equation.An equation is a statement that two quantities are equivalent.For example, this linear equation: x + 1 = 4 means that when we add 1 to the unknown value, ‘x’, the answer is equal to 4.To solve linear equations, you add, subtract, multiply and divide both sides of the equation by numbers and variables, so that you end up with a single variable on one side and a single number on the other side. As long as you always do the same thing to BOTH sides of the equation, and do the operations in the correct order, you will get to the solution.For this example, we only need to subtract 1 from both sides of the equation in order to isolate 'x' and solve the equation:x + 1 - 1 = 4 - 1Now simplifying both sides we have:x + 0 = 3So:x = 3With some practice you will easily recognise what operations are required to solve an equation.Here are possible ways of solving a variety of linear equation types.Example 1, Solve for ‘x’ :x + 1 = -31. Subtract 1 from both sides:x + 1 - 1 = -3 - 12. Simplify both sides:x = -4Example 2, Solve for ‘x’ :-2x = 121. Divide both sides by -2:2. Simplify both sides:x = -6Example 3, Solve for ‘x’ :1. Multiply both sides by 3:2. Simplify both sides:x = -6Example 4, Solve for ‘x’ :2x + 1 = -171. Subtract 1 from both sides:2x + 1 - 1 = -17 - 12. Simplify both sides:2x = -183. Divide both sides by 2:4. Simplify both sides:x = -9Example 5, Solve for ‘x’ :1. Multiply both sides by 9:2. Simplify both sides:3x = 363. Divide both sides by 3:4. Simplify both sides:x = 12Example 6, Solve for ‘x’ : 1. Multiply both sides by 3: 2. Simplify both sides: x + 1 = 21 3. Subtract 1 from both sides: x + 1 - 1 = 21 - 1 4. Simplify both sides:x = 20Example 7, Solve for ‘x’ :7(x - 1) = 211. Divide both sides by 7:2. Simplify both sides:x - 1 = 33. Add 1 to both sides:x - 1 + 1 = 3 + 14. Simplify both sides:x = 4Example 8, Solve for ‘x’ :1. Multiply both sides by 5:2. Simplify both sides:3(x - 1) = 303. Divide both sides by 3:4. Simplify both sides:x - 1 = 105. Add 1 to both sides:x - 1 + 1 = 10 + 16. Simplify both sides:x = 11Example 9, Solve for ‘x’ :5x + 2 = 2x + 171. Subtract 2x from both sides:5x + 2 - 2x = 2x + 17 - 2x2. Simplify both sides:3x + 2 = 173. Subtract 2 from both sides:3x + 2 - 2 = 17 - 24. Simplify both sides:3x = 155. Divide both sides by 3:6. Simplify both sides:x = 5Example 10, Solve for ‘x’ :5(x - 4) = 3x + 21. Expand brackets:5x - 20 = 3x + 22. Subtract 3x from both sides:5x - 20 - 3x = 3x + 2 - 3x3. Simplify both sides:2x - 20 = 24. Add 20 to both sides:2x - 20 + 20 = 2 + 205. Simplify both sides:2x = 226. Divide both sides by 2:7. Simplify both sides:x = 11

6 0

3 years ago

Read 2 more answers

Match the function in the left column with its period in the right column.

kiruha [24]

The results for the matching between function and its period are:

Option 1 - Letter D
Option 2 - Letter A
Option 3 - Letter C
Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

$\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}$

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}$

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

$\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi$

Thus, the option 1 matches with the letter D.

2) Option 2

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}$

Thus, the option 2 matches with the letter A.

3) Option 3

$\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{2} =\pi$

Thus, the option 3 matches with the letter C.

4) Option 4

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{8} =\frac{\pi }{4}$

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

6 0

2 years ago

When writing linear equations, how do you determine which form of a line to use?

emmainna [20.7K]

When given two points, use point-slope form
When given a point and the intercept, use slope-intercept form.
When given a point and the slope, use point slope form.

6 0

3 years ago

Read 2 more answers

A dinosaur park cost $5.00 to enter plus $0.75 taxes. How much does it cost if a family of 4 went to the park

Alekssandra [29.7K]

I think 20.75 i’m not completely sure

8 0

3 years ago