Answer:
a)Both X and Y can be well approximated by normal random variables.
Step-by-step explanation:
For each individual, there are only two possible outcomes. Either they are right-handed, or they are left-handed. This means that we can solve this problem using concepts of the binomial probability distribution.
Binomial probability:
Probability of exactly x sucesses on n repeated trials, with probability p.
The binomial probability can be well approximated by normal random variables, using the expected value
and the standard deviation 
Let X be the number of males (out of the 100) who are left-handed.
and
. Can be well approximated.
Let Y be the number of females (out of the 80) who are left-handed.
and
. Can be well approximated.
The correct answer is
a)Both X and Y can be well approximated by normal random variables.
Answer:
D. The sum of twice number and six is no more than five.
Step-by-step explanation:
In the inequality,

The number (n) is multiplied by (2), therefore options (A) and (B) can be ruled out since they have the statement, "twice the sum of a number and six". Moreover, one can see the inequality sign indicates that this value is less than or equal to (5). Thus, one of the possible solutions to this equation is (5), therefore, option (C) is incorrect. Therefore, the only remaining correction option is option (D).
Step-by-step explanation:
x=2
y=0
.................
The midpoint of a segment divides the segment into equal halves
The other endpoint is 1- 5i
<h3>How to determine the missing endpoint </h3>
The coordinates are given as:
Point 1: 7 + i
Midpoint: 3 - 2i
Represent the other endpoint with x.
So, we have:
2 * Midpoint = Point 1 + x
This gives


Collect like terms

Evaluate the like terms

Hence, the other endpoint is 1- 5i
Read more about midpoints ta:
brainly.com/question/9635025
To work out the probability of both errors occuring, simply multiply the probability of the first error by the probability of the second error. Therefore the probability of both errors occurring is 0.2 * 0.3 = 0.06.