Which is the horizontal axis

Fill in the missing expression

padilas [110]

Answer:

The complete table is:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ 7a + 2b ] + [ 3a + 8 ] + [ 0 ] = [10a + 2b + 8 ]

Explanation:

You can determine the content of each box by subtraction, running the rows and the columns.

The expressions are:

[ 5a ] + [ ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ ]

+ + + +

[ ] + [ ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

1. First row:

[ 5a ] + [ ] + [ 4a ] = [ 10a + 3 ]

[ ] = [10a+ 3] - [ 4a ] - [ 5a ] = 10a - 4a - 5a + 3 = a + 3

2. Second colum:

[ a + 3 ] + [ 4 + a ] + [ ] = [ 3a + 8 ]

[ ] = [ 3a + 8 ] - [ a + 3 ] - [ 4 + a ] = 3a - a + a + 8 - 4 - 3 = a + 1

So far, you have completed this:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ ]

+ + + +

[ ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

3. Complete the row 3:

[ ] + [ a + 1 ] + [ -3a ] = [ 1 ]

[ ] = [ 1 ] - [ a + 1 ] - [ -3a ] = - a + 3a + 1 - 1 = 2a

So far, you have completed this:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

4. Complete the fourth column:

[ 10a + 3 ] + [ ] + [ 1 ] = [10a + 2b + 8 ]

[ ] = 10a + 2b + 8 - 10a - 3 - 1 = 2b + 4

So far, this is the results:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

5. Complete the second row:

[ 2b ] + [ 4 + a ] + [ ] = [ 2b + 4 ]

[ ] = [ 2b + 4 ] - [ 2b ] - [ 4 + a ] = 2b - 2b + 4 - 4 - a = - a

So far:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

6. Complete the first colum:

[ 5a ] + [ 2b ] + [2a ] = [ ]

[ ] = [ 7a + 2b ]

So far:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ 7a + 2b ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

7. Complete the last row:

[ 7a + 2b ] + [ 3a + 8 ] + [ ] = [10a + 2b + 8 ]

[ ] = [10a + 2b + 8 ] - [ 7a + 2b ] - [ 3a + 8 ] = 0

The complete table is:

[ 5a ] + [ a + 3 ] + [ 4a ] = [ 10a + 3 ]

+ + + +

[ 2b ] + [ 4 + a ] + [ -a ] = [ 2b + 4 ]

+ + + +

[ 2a ] + [ a + 1 ] + [ -3a ] = [ 1 ]

= = = =

[ 7a + 2b ] + [ 3a + 8 ] + [ 0 ] = [10a + 2b + 8 ]

5 0

3 years ago

Last one that I need help

Zina [86]

269 is the answer. Each one is divided by 2.
4304/2=2152
2152/2=1076
1076/2=538
538/2=269

4 0

3 years ago

A protein mix claims to contain a bonus of 20% more mix than the usual size container. If the bonus size contains 18 ounces of m

agasfer [191]

Answer:

The usual size of the container is 15 ounces.

Step-by-step explanation:

Consider the provided information.

A protein mix claims to contain a bonus of 20% more mix than the usual size container.

Let the usual size of the container was x ounces.

They increase 20% of usual size and the bonus size is 18 ounces.

Therefore, the new size should be:

$x+20\%x=18$

$x(1+0.20)=18$ (∴20%= $\frac{20}{100}$ =0.20)

$x(1.20)=18$

$x=\frac{18}{1.20}$

$x=15$

Hence, the usual size of the container is 15 ounces.

3 0

3 years ago

Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)

Marina86 [1]

<h2>Question :</h2>

Write the equation of a line that is perpendicular to the given line and that passes through the given point. y=2/3x+9 m (–6, 5)

<h2>Answer :</h2>

y = -3/2x - 4

<h2>Explanation :</h2>

y = mx + c

*m = gradien

•>looking for gradients

y=2/3x+9

m1 = 2/3

m2 = -3/2

•>line equation (-6,5)

y - y1 = m(x - x1)

y - 5 = -3/2(x - (-6))

y - 5 = -3/2(x + 6)

y - 5 = -3/2 - 9

y = -3/2x - 9 + 5

y = -3/2x - 4

8 0

3 years ago

Find the collame of boid of dimension 16cm X 10m x 6cm.

swat32

Question: Find the volume of cuboid of dimension 16cm X 10cm x 6cm.

Answer: Given Length=16cm, Breadth=10cm, Height=6cm

Using Volume formula for cuboid:-

$volume = l \times b \times h$

$→16 \times 10 \times 6$

$→960 \: cm^{3}$

So, volume of cuboid is 960 cm³

7 0

2 years ago