It was given that
1 gal = 20 lbs of CO2
1 gal = 25 miles distance
Thus,
15000 miles/year ( 1 gal / 25 miles ) ( 20 lbs CO2 / 1 gal ) = 12000 CO2
<span>If Harry drives 15,000 miles per year, his vehicle will add 12000 pounds of CO2 to the atmosphere.</span>
Answer:
The distributive property.
I believe
4 and 6
4/1 and 6/1<span />
Integrate <span>f ''(x) = −2 + 36x − 12x2 with respect to x:
f '(x) = -2x + (36/2)x^2 - (12/3)x^3 + c. Find c by letting x = 0 and using f(0)=8.
Then f '(0) = -2x + 18x^2 - 4x^3 + c = 18 (which was given).
Then -0 + 0 - 0 + c = 18, so c = 18 and
f '(x) = </span>-2x + 18x^2 - 4x^3 + 18.
Go through the same integration process to find f(x).
