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lara31 [8.8K]
3 years ago
12

BD−→− bisects ∠ABC such that m∠ABD = (4x−5)∘ and m∠DBC = (3x+2)∘.

Mathematics
1 answer:
Rzqust [24]3 years ago
3 0

Answer:

\angle ABC=(46)^{\circ}

Step-by-step explanation:

Given: BD bisects \angle ABC

\angle ABD=(4x-5)^{\circ}\\\angle DBC=(3x+2)^{\circ}

To find: \angle ABC

Solution:

A bisector of an angle divides it into angles of equal measures.

As BD bisects \angle ABC, \angle ABD=\angle DBC

Put \angle ABD=(4x-5)^{\circ}\,,\,\angle DBC=(3x+2)^{\circ}

\angle ABD=\angle DBC\\(4x-5)^{\circ}=(3x+2)^{\circ}\\4x-3x=2+5\\x=7^{\circ}

So,

\angle ABD=(4x-5)^{\circ}=(4(7)-5)^{\circ}=(28-5)^{\circ}=(23)^{\circ}\\\angle DBC=(3x+2)^{\circ}=(3(7)+2)^{\circ}=(21+2)^{\circ}=(23)^{\circ}

\angle ABC=\angle ABD+\angle DBC\\=(23)^{\circ}+(23)^{\circ}\\=(46)^{\circ}

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8 0
4 years ago
I NEED HELP FAST PLEASE!!!
uranmaximum [27]
I think it is A as $16,845,562,487,550/ 3.11591917 x 10^8 is <span>54062.89948 so the nearest answer is A

</span>
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