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Arada [10]
4 years ago
13

1 What is the range of the following numbers? 12, 20, 18, 25,6

Mathematics
2 answers:
rosijanka [135]4 years ago
7 0
You take the largest and smallest number in the set of numbers and subtract it

ex:

25 - 6 = 19
aliina [53]4 years ago
3 0
So the range is 19 cuz 25-6=19
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In ΔIJK, the measure of ∠K=90°, the measure of ∠J=76°, and JK = 3.6 feet. Find the length of IJ to the nearest tenth of a foot.
Nataly_w [17]
This is my answer
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3 0
3 years ago
I dont know what it is and its for <br> ten pointsss
labwork [276]

Answer:

1

Step-by-step explanation:

anything with a power of 0 is 1

7 0
3 years ago
Read 2 more answers
Rewrite the equation without absolute value, thanks!
34kurt

Since x - 3 < 0 for -2 < x < 3, |x-3| = -(x-3)

Since x + 2 > 0 for -2 < x < 3, |x+2| = x+2

Since x - 5 < 0 for -2 < x < 3, |x-5| = -(x-5).

So y = -(x-3) + (x+2) -(-(x-5)) = 3 - x + x + 2 + x - 5 = x.

y = x, if -2 < x < 3.

4 0
3 years ago
Find Sn for the given arithmetic series a1=-26 d=-9 n=24
ryzh [129]

Answer:

- 3108

Step-by-step explanation:

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a_{1} + (n - 1)d ]

Substitute the given values into the formula

S_{24} = \frac{24}{2} [ (2 × - 26) + (23 × - 9) ]

                          = 12 ( - 52 - 207 )

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5 0
3 years ago
How long does it take you and students 2 and 3 to clean up a 12 ft. X 12 ft wall covered in graffiti? Besides the answer (be spe
Ostrovityanka [42]

Answer:

At a combined speed of 6 in/min, it takes us 24 mins to clean the wall

Step-by-step explanation:

Since the question did not provide the speed with which each student cleans, we can make assumptions. This is so that we can solve the question before us

Assuming student 1 cleans at a speed of 2 inches per minute, student 2 cleans at a speed of 2½ inches per minute & student 3 cleans at a speed of 1½ inches per minute.

Let's list the parameters we have:

Height of wall (h) = 12 ft, Speed (student 1) = 2 in/min, Speed (student 2) = 2½ in/min, Speed (student 3) = 1½ in/min

Speed of cleaning wall = Height of wall ÷ Time to clean wall

Time to clean wall (t) = Height of wall ÷ Speed of cleaning wall

since students 1, 2 and 3 are working together, we will add their speed together; v = (2 + 2½ + 1½) = 6 in/min

1 ft = 12 in

Time (t) = h ÷ v = (12 * 12) ÷ 6 = 144 ÷ 6

Time (t) = 24 mins

8 0
3 years ago
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