Answer:
The distribution is approximately normal with mean = 2.8 and standard error = 0.4
Step-by-step explanation:
We are given;
Mean; μ = 2.8
Standard deviation; σ = 4
Sample size; n = 100
Now, the central limit theorem states that the sample mean with a sample size(n) from a population mean (μ) and population standard deviation(σ) will, for large value of n, have an approximately normal distribution with mean μ and standard error as (σ/√n)
The sample size is 100 and thus it's very large because it's bigger than minimum of 30 for approximate distribution.
Thus, SE = (σ/√n) = 4/√100 = 4/10 = 0.4
Thus,from the central limit theorem I described, we can say that the distribution is approximately normal with mean = 2.8 and standard error = 0.4
Solution Steps:
1/12 x 3/12
3/144
Simplify = 1/48
Hopefully this is correct
Answer:
that is easy false hope u get it to By 7:10
Answer:
6.73
Step-by-step explanation:
6 (whole number) 8/11 is 6.7272 approximately 6.73 (3 s.f)
the 6 whole number gives the 6.
8/11 is 0 and using the whole long division method gives 0.7272...
cause when you add zero to 8 it becomes 80 and 11 goes into 80, 7 times giving 77.
subtracting 77 from 80 gives 3 adding 0 becomes 30 and 11 into 30 is 2 giving 22
I hope this helps
I recommend using online calculators for example, look up your subject and then put “calculator” after it. Like for example, “Find the slope calculator”
