Answer:
-11
Step-by-step explanation:
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Answer:
1 ad 12
Step-by-step explanation:
Answer:
A, D, F
Step-by-step explanation:
It is convenient to let a calculator or spreadsheet evaluate the function for you. Reflection over the y-axis means x is replaced by -x in the original function definition.
The values that show up on the reflected graph are ...
(-7, -10.206)
(0.5, -0.221)
(9, -0.003)
Part A:
To determine the values of the times to which the height of the two cannon balls are the same, we equate the given functions.
H(t) = g(t)
Substitute the expressions for each.
-16t² + 48t + 12 = 10 + 15.2t
Transpose all the terms to the left-hand side of the equation.
-16t² + (48 - 15.2)t + (12 - 10) = 0
Simplifying,
-16t² + 32.8t + 2 = 0
The values of t from the equation are 2.11 seconds and -0.059 seconds
Part B:
In the context of the problem, only 2.11 seconds is acceptable. This is because the second value of t which is equal to -0.059 seconds is not possible since there is no negative value for time.
Answer: ![\bold{3\sqrt{2x}-36\sqrt x}](https://tex.z-dn.net/?f=%5Cbold%7B3%5Csqrt%7B2x%7D-36%5Csqrt%20x%7D)
<u>Step-by-step explanation:</u>
![7(3\sqrt{2x})-3(3\sqrt{16x})-3(3\sqrt{8x})\\\\=21\sqrt{2x}-9\sqrt{16x}-9\sqrt{8x}\\\\=21\sqrt{2x}-9\cdot 4\sqrt x-9\cdot 2\sqrt{2x}\\\\=21\sqrt{2x}-36\sqrt x-18\sqrt{2x}\\\\=(21-18)\sqrt{2x}-36\sqrt x\\\\=3\sqrt{2x}-36\sqrt x](https://tex.z-dn.net/?f=7%283%5Csqrt%7B2x%7D%29-3%283%5Csqrt%7B16x%7D%29-3%283%5Csqrt%7B8x%7D%29%5C%5C%5C%5C%3D21%5Csqrt%7B2x%7D-9%5Csqrt%7B16x%7D-9%5Csqrt%7B8x%7D%5C%5C%5C%5C%3D21%5Csqrt%7B2x%7D-9%5Ccdot%204%5Csqrt%20x-9%5Ccdot%202%5Csqrt%7B2x%7D%5C%5C%5C%5C%3D21%5Csqrt%7B2x%7D-36%5Csqrt%20x-18%5Csqrt%7B2x%7D%5C%5C%5C%5C%3D%2821-18%29%5Csqrt%7B2x%7D-36%5Csqrt%20x%5C%5C%5C%5C%3D3%5Csqrt%7B2x%7D-36%5Csqrt%20x)