Answer:
<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>
Step-by-step explanation:
The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.
We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.

Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.
Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.

Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.
<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>
1.5 deep.
you subtract 2.25 of air space from the total depth 3.75
3.75-2.25=1.5
Answer: 56 times
Pls mark brainleist i really need it
Throw rug with diameter of 12 feet what is the approximate
Answer: 0.09 hours
Step-by-step explanation:
You are owed $1.76 in overtime pay.
The hourly rate for overtime is $19.50 per hour.
To find the number of hours owed, you need to divide the amount owed by the amount owed per hour.
The number of hours you are owed is therefore:
= Amount owed / Amount owed per hour
= 1.76 / 19.50
= 0.09 hours