Find the perimeter of the window to the nearest hundredth. if the bottom is 3ft

Mathematics

1 answer:

aleksklad [387]3 years ago

4 0

Where’s the pic i need more info

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I need help filling the blanks.

hodyreva [135]

Answer:

Not congruent.

Step-by-step explanation:

They are not congruent because the first one has ASA and the second one is AAS.

8 0

3 years ago

You have $10 to go bowling with your friends. You need to rent shoes for $4. Each game (g) costs $3. Write and solve an equation

dexar [7]

Answer:

The equation is: x = (y - $4) / g

Where x is the number of games you can play;

y is the amount you have

and g is the cost of each game

You can play only 2 games

Step-by-step explanation:

From the question, you have $10 to go bowling and you need to rent shoes for $4. Hence, after renting the shoes, you will have $10 - $4 left, that is you will have $6 left. To determine the number of games you can play, that will be the amount you have left after renting shoes divided by the cost of each game.

Let the number of games you can play be x games

and the amount you have be y

and the cost of each game be g

Hence,

x = (y - $4) / g

From the question,

y = $10

and g = $3

∴ x = ($10 - $4)/ $3

x = $6 / $3

x = 2

Hence, you can play only 2 games

6 0

3 years ago

Find a number C such that the polynomial p(x)= -x+4x^2+Cx^3-8x^4

Ksenya-84 [330]

Answer:

C = 2

Step-by-step explanation:

$p(x)= -x+4x^2+Cx^3-8x^4 \\ \\ \because \: given \: polynmial \: has \: zero \: at \: \\x = \frac{1}{4} \\ \\ \implies \: p\bigg(\frac{1}{4} \bigg) = 0...(1) \\ \\ plug \: x = \frac{1}{4} \: in \: p(x) \: we \: find \\ \\ p \bigg(\frac{1}{4} \bigg) = - \frac{1}{4} + 4 {\bigg(\frac{1}{4} \bigg)}^{2} + c {\bigg(\frac{1}{4} \bigg)}^{3} - 8 {\bigg(\frac{1}{4} \bigg)}^{4} \\ \\ 0 = - \frac{1}{4} + \cancel 4 \times {\frac{1}{\cancel{16} } } + c {\bigg(\frac{1}{64} \bigg)} - \cancel 8 \times \frac{1}{\cancel{256} } \\ \\0 =\cancel{ - \frac{1}{4}} + \cancel {{\frac{1}{4} }} + c {\bigg(\frac{1}{64} \bigg)} - \times \frac{1}{32} \\ \\0 = c {\bigg(\frac{1}{64} \bigg)} - \frac{1}{32} \\ \\c {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32} \\ \\ c = \frac{1}{32} \times 64 \\ \\ c = 2$