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alisha [4.7K]
3 years ago
10

Use the graph below to answer the following question.

Mathematics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

Ce_2(SeC_4)_2 is least soluble at high temperatures.  

Step-by-step explanation:

The compound that has least solubility when the temperature increases is the one that has the least value along y-axis <em>(solubility)</em> for greater values along x- axis <em>(temperature).</em>

From the graph we see that KNO_3 is most soluble at high temperatures <em>(in fact its solubility increases with increase in temperature)</em>, and Ce_2(SeC_4)_2 is least soluble for high temperatures <em>(its solubility decreases with increase in temperature) .</em>

Thus,<em> </em>Ce_2(SeC_4)_2 is least soluble at high temperatures.

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Mashcka [7]
The answer would be B
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4 years ago
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which of the following is the result of using the remainder theorem to find F(-1) for the polynomial function F(x) = -x^3+6x^2-4
balandron [24]

Answer:

d). 22

Step-by-step explanation:

add the -1 for x then solve

7 0
3 years ago
Determine whether PQ and UV are parallel,
lys-0071 [83]

Answer:

The answer is below

Step-by-step explanation:

The slope of a line (m) is given by:

m=\frac{y_2-y_1}{x_2-x_1}

Two lines are parallel if they have the same slope and perpendicular if the product of their slope is -1.

1)

Slope\ of\ PQ=\frac{1-(-2)}{9-(-3)}=\frac{1}{4}  \\\\Slope\ of\ UV=\frac{-2-6}{5-3}=-4

Since the product of their slope is -1, they are perpendicular

2)

Slope\ of\ PQ=\frac{1-7}{2-(-10)}=-\frac{1}{2}  \\\\Slope\ of\ UV=\frac{1-0}{6-4}=\frac{1}{2}

Since the slope is not the same or product of their slope is not -1, they are neither parallel or perpendicular

3)

Slope\ of\ PQ=\frac{8-1}{9-1}=\frac{7}{8}  \\\\Slope\ of\ UV=\frac{8-1}{2-(-6)}=\frac{7}{8}

Since the slopes are the same, they are parallel

4)

Slope\ of\ PQ=\frac{3-0}{9-(-4)}=\frac{3}{4}  \\\\Slope\ of\ UV=\frac{6-(-3)}{8-(-4)}=\frac{3}{4}

Since the slopes are the same, they are parallel

5)

Slope\ of\ PQ=\frac{1-2}{0-(-9)}=-\frac{1}{9}  \\\\Slope\ of\ UV=\frac{-1-8}{-2-(-1)}=9

Since the product of their slope is -1, they are perpendicular

6 0
3 years ago
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Answer:

y=2x+4 so C

Step-by-step explanation:

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A line with a slope of -2/3 and a y-intercept of 4; in slope-intercept form
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y = mx + b. The slope-intercept form for this would be y = -2/3x + 4.
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3 years ago
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