Jason = J Bill = B Sharon = S
J = 5+B
B= 2×S
J= 5+ (2×S)
The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
Answer:
3 ways
Step-by-step explanation:
ex: 3/6 "3 to 6" 3:6
Answer:
A
Step-by-step explanation:
Sine we can figure out side XY by using Pythagorean Theorem (A^2+B^2=C^2) and find that XY= 5, We can use Soh Cah Toa (The ways I remember to use value charts) and we know that Cosine uses Adjacent over Hypotenuse in which therefore the answer would be 5/13
