Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,

Here,
,Perpendicular AB = 4000


Solving for BC, we get,

(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
If you would like to solve the system of linear equations, you can do this using the following steps:
2x - y = -1 ... y = 2x + 1
2x + y = -7 ... y = -7 - 2x
The correct result would be: y = 2x + 1, <span>2x + y = -7.</span>
Answer:
5
Step-by-step explanation:
x^2 - 10x + 16 = 0
factor
(x - 2)(x - 8) = 0
roots
x = {2, 8}
mean of roots
a = (2 + 8) /2
a = 5
Answer:
pretty sure its -2,3 :)
Step-by-step explanation:
Answer:
32 units.
Step-by-step explanation:
look up a picture of a 306090 triangle, it will make sense :)