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Feliz [49]
3 years ago
13

What Is the solution to the above system of equations? 2x+3y=11

Mathematics
1 answer:
Citrus2011 [14]3 years ago
3 0
The answer would be C.
Hope this helps! (:
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How do you write 3/4 as percentage?
german
3/4 is 75%

for this think of them as quarters 4 quarters is 100 %, 2 quarters is 50% so 3 quarters would be 75%

or you could just do 3 divided by 4 then times that by 100
5 0
3 years ago
Read 2 more answers
For Anya's birthday her father gave out colorful birthday hats that were cone shaped. Anya was very happy that day. The opening
Darya [45]
Anya will have 5cm of candy sorry if it’s
Wrong
6 0
3 years ago
PLEASE PLEASE I SUCK AT MATH AND ITS ALL DUE FRIDAY PLEASE 10 piont !!! Select all the correct systems of equations.
alekssr [168]

Answer:

2x + y = 17

-6x = 3y - 51

Step-by-step explanation:

You get an infinite number of solutions when two equations are really just the same. This means you can convert one into the other simply by multiplying one to get the other.

In the above answer, if you multiply the above by -3 you get:

-6x -3y = -51

which is of course -6x = 3y - 51

So that is an example of a pair that has infinite solutions.

To find all of them, you'd carefully have to compare each 2 and see if there is a multiplier to convert one into the other. You can do that!

4 0
3 years ago
Cone A is divided into Cone B and Frustum C. B A 12cm C 20cm 20cm Express the volume of Frustum C as a fraction of the volume of
zaharov [31]

The volume of the frustum is volume of the whole cone(A) minus the smaller cone(B) which is would give the volume of frustum(C) = 256cm³

<h3>Calculation of a frustum</h3>

The volume of cone A V=πr²h/3

Where radius = 20cm

The volume of cone B = V=πr²h/3

Where radius = 12cm

Therefore volume of frustum =

V=π * 20² * h/3 - π * 12² *h/3

The variables will cancel out each other

V = 20² - 12²

V = 400- 144

V = 256cm³

Therefore, the volume of the frustum(C) = 256cm³

Learn more about cone here:

brainly.com/question/1082469

#SPJ1

7 0
2 years ago
Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of
ser-zykov [4K]

Answer: graph E.


A geometric sequence can be written as:

a_{n} = a_{1} \cdot r^{(n - 1)}

where:

a₁ = first term = 4

r = ratio = 0.5


Substituting the numbers, we have:

a_{n} = 4 \cdot (\frac{1}{2})^{n-1}

or else

f(x) = 4 \cdot (\frac{1}{2})^{x - 1}


This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).


In order to choose between graph B and E, let's evaluate the function in two different points:

f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4

f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.




3 0
3 years ago
Read 2 more answers
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