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photoshop1234 [79]
3 years ago
7

-17-3(2+13)+24 What is the answer?

Mathematics
2 answers:
san4es73 [151]3 years ago
7 0

Answer:

-104

Step-by-step explanation:

In order to get the answer to this question you will have to use PEMDAS:

-17-3(2+13)+24

P goes first

2+13=15

-17-3\times15+24

M goes next

3\times15=45

-17-45+24

A goes next

45+24=87

-17-87

Using KCC

-17-87=-104

=-104

Therefore your answer is "-104."

Hope this helps.

yawa3891 [41]3 years ago
6 0
The answer will be - 38
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Using the binomial theorem , obtain the expansion of :
andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1  6  15  20  15  6  1

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Increasing powers of 3x from (3x)^{0} to (3x)^{6}

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--------------------------------------------------------------------------------------

(1-3x)^{6}

= 1.1^{6}(-3x)^{0} + 6.1^{5}(-3x)^{1} + 15.1^{4}(-3x)^{2} + 20.1^{3}(-3x)^{3} + 15.1²(-3x)^{4} + 6.1^{1}(-3x)^{5} + 1.1^{0}(-3x)^{6}

= 1 - 18x + 135x² - 540x³ + 1215x^{4} - 1458x^{5} + 729x^{6}

----------------------------------------------------------------------------------

Collecting like terms from both expressions

(1+3x)^{6} + (1-3x)^{6}

= 2 + 270x² + 2430x^{4} + 1458x^{6}

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1  5  10  10  5  1

Decreasing powers of 1 from 1^{5} to 1^{0}

Increasing powers of 2x from (2x)^{0} to (2x)^{5}

(1+2x)^{5}

= 1.1^{5}(2x)^{0} + 5.1^{4}(2x)^{1} + 10.1^{3}(2x)^{2} + 10.1^{2}(2x)^{3} + 5.1^{1}(2x)^{4}+ 1.1^{0}(2x)^{5}

= 1 + 10x + 40x² + 80x³ + 80x^{4} + 32x^{5}

8 0
3 years ago
The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi
inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.        

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

\displaystyle\frac{dr}{dt} = -7\text{ inch per second}

The volume is decreasing at a constant rate.

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We have to find the rate of change of height with respect to time.

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V = \displaystyle\frac{1}{3}\pi r^2 h

Instant volume =

525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}

Differentiating with respect to t,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)

Putting all the values, we get,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0
3 years ago
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