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Setler [38]
3 years ago
6

What is the area for 10 and 6 1/2

Mathematics
1 answer:
schepotkina [342]3 years ago
6 0

Answer:

65 units squared

Step-by-step explanation:

Why:area is base length times width. Considering what you gave me, 10 * 6.5 =65

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1/x + 3 = x +10/ x - 2
qwelly [4]

Answer:

(x+3)(x-2)= x - 2

x^2 + x - 6 = x - 2

x^2 - 6 = -2

x^2 - 4 = 0

x^2 = 4

x = 2, -2

7 0
3 years ago
This is urgent, please answer! <br><br> What is the area of this composite figure?
Reika [66]
Answer: 978 in^2

Explanation:
30 x 24 = 720
12 x 9 = 108
(15 x 20)/2 = 150
150 + 108 + 720 = 978
4 0
3 years ago
Read 2 more answers
H-5.3=2.6 solve the equation
Alex
The answer should be H= 7.9
7 0
3 years ago
My answer was 16, so i thought as a fraction it would 16/100, but i think its 1/6 in the correct way, i dont really know.
larisa [96]

Answer: You're right.

Step-by-step explanation: There are only 6 parts to a die. so the change of landing on 6 would be 1/6, bc there's only 1-6 once.

4 0
3 years ago
Can I have help with this question? I need the answer with explanation
Serga [27]

Answer:

44,39 in

Step-by-step explanation:

To find the space diagonal (whatever it's called in English) you begin looking at the bottom of the box. We want to know the diagonal since the diagonal is one of the sides of the other triangle.

To do this we can start by using trigonometry. (SOH-CAH-TOA)

We need to use Sin t. (Since we wanna know the hypothenuse and we have the opposite.)

So...

Sin(40) = 24 in ÷ <em>h</em>

Then we need to actually be able to calculate this, which we will be able to do if we multiply with h on both sides.

hSin(40) = 24 in

Like that. And now we can divide both sides with Sin(40). So we calculate 24 in devided by Sin(40).

h = 24 in ÷ Sin(40) = 37,34 in

Okay so now we now the diagonal, 37,34 in. Now we can use Pythagorean theorem. (2a+2b=2c and c = square root of (2a+2b))

37,34 in^(2) + 24 in^(2) = 1970,28

And now we take the square root of 1970,28.

Which is about 44,39 in.

<em>If you're not familiar with these concepts I suggest you</em><em> </em><em>search</em><em> </em><em>them</em><em> </em><em>up</em><em>.</em>

3 0
2 years ago
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