Two rules come into play here:
1) We cannot divide by zero. Thux, x cannot = -3.
2) The domain of the square root function is (0, infinity). This is the dominant limiting factor.
x + 3 must be > 0. Thus, x must be > -3
The domain of this expression is (-3, infinity).
Answer:
4⋅(a⋅2)
2⋅(4⋅a)
8a
Step-by-step explanation:
(4⋅a)⋅2
4⋅(a⋅2) This is the same by the associative property of multiplication
2⋅(4⋅a) This is the same by the associative property of multiplication and the communicative property of multiplication
4⋅2⋅a⋅2 This brings in an extra 2 so it is not the same.
8a 4*2 = 8 so this is the same
4⋅2+a⋅2 This is the not the same 8+2a is not the same as 8a
The correct answer is 8/x + 4.
Answer:
{0, 1, 2, 3, 4} --> 96 5-digit numbers possible with this set.
Step-by-step explanation:
i dunno, i kinda just searched it up
link: https://gmatclub.com/forum/how-many-five-digit-numbers-can-be-formed-using-digits-91597.html#:~:text=If%200%20is%20included%3A,numbers%20possible%20with%20this%20set.
