Help me please...!!!

Change this root into a power.

Nadusha1986 [10]

Answer:

3^2/5

Step-by-step explanation:

7 0

2 years ago

Is 6^-2 positive or negative? Explain.

Gnoma [55]

Answer:

It's positive when you have 6^-2 it's the same as having $(\frac{1}{6})^{2} \\$ . So 6^-2 it's 1/36.

Step-by-step explanation:

7 0

2 years ago

In exercises 1 and 2, Find the value of x.

Kruka [31]

From the given picture, we can see that 2 sides are congruen, then the given triangle is an isosceles triangle. In this triangle the base angles are congruent, so we can draw the following picture:

Now, since interior angles of any triangle add up to 180 degrees, we have

$x+\frac{x}{2}+\frac{x}{2}=180$

By combining similar terms, we get

$\begin{gathered} \frac{4}{2}x=180 \\ 2x=180 \end{gathered}$

Then, x is given as

$\begin{gathered} x=\frac{180}{2} \\ x=90 \end{gathered}$

Therefore, the answer is x=90 degrees

4 0

10 months ago

What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0

2 years ago

Solve ry + s = tx - m for y. Explain each step in your solution.

sergeinik [125]

y = (t x - m -s)/r

Step-by-step explanation:

Step 1 :

Given,

r y + s = t x - m

=> r y = t x - m -s

=> y = (t x - m -s)/r

Step 2 :

A) r can take any values except 0.

This is because when r = 0, the denominator becomes 0 and division by 0 is undefined

The limitation for r is r should not be equal to 0

The other variables can take any value. Hence the other variables do not have any limitation

7 0

2 years ago