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3 years ago

Where would 3.8 go on the number line?

Mathematics

1 answer:

nata0808 [166]3 years ago

3 0

Answer:

Between 3 and 4

Step-by-step explanation:

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Find the angle that makes them supplementary.

Semmy [17]

Answer:

130,110,40,90,165

Step-by-step explanation:

supplementary angles add up to 180

so 180-50= 130

180-70=110

etc

7 0

3 years ago

Simplify the given algebraic expression.<br> 8(5y - 8) - (5y + 3)

RoseWind [281]

Answer:

35y - 67

Step-by-step explanation:

8(5y - 8) - (5y + 3)

Multiply the 8 with what is in the parentheses.

40y - 64 - 5y + 3

Subtract like terms.

35y - 67

7 0

3 years ago

Read 2 more answers

Centimeter cubes were used to build the prism. What is the volume of the prism?

ioda

Volume = lxwxh .

Centimeter square

5 0

3 years ago

Read 2 more answers

a homeowner is planning an addition to her house. she wants the new family room to be a rectangle with an area of 192 feet. The

kozerog [31]

Answer:

length=16feet width=12feet

Step-by-step explanation:

This may not be the best way, i just stumbled upon the answer using this.

I knew 14*14=196, which is relatively close to 192.

Then, I took away 2 from one of the 14s and added it to the other 14.

14-2=12 14+2=16

Apparently, 16*12 is 192, so that's the answer.

6 0

3 years ago

Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function.

marishachu [46]

Answer:

$\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

Step-by-step explanation:

We have been given the function

$f(x)=-2x^2+4x^3+3x^2+18$

From the rational zeros theorem, we have

$\text{Possible rational zeros}=\pm\frac{\text{Factors of constant term}}{\text{Factors of leading coefficient}}$

From the given function,

Leading coefficient = 2

Factors of 2 are 1,2

Constant term = 18

Factors of constant term = 1, 2, 3, 6, 9, 18

Hence, we have

$\text{Possible rational zeros}=\pm\frac{1,2,3,6,9,18}{1,2}\\\\\text{Possible rational zeros}=\pm1,\pm\frac{1}{2},\pm2,\pm3,\pm\frac{3}{2},\pm6,\pm9,\pm\frac{9}{2},\pm18$

6 0

3 years ago