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Musya8 [376]
3 years ago
13

Need help with these questions. show work to plzzzz

Mathematics
1 answer:
Vitek1552 [10]3 years ago
6 0

2.\\k(x)=2x^2-3\sqrt{x}\\\\k(9)\to\text{put the value of x = 9 to the equation of the function:}\\\\k(9)=2(9)^2-3\sqrt9=2(81)-3(3)=162-9=153\to\boxed{(4)}\\\\3.\\3(x^2+2x-3)-4(4x^2-7x+5)\qquad\text{use distributive property}\\\\=(3)(x^2)+(3)(2x)+(3)(-3)+(-4)(4x^2)+(-4)(-7x)+(-4)(5)\\\\=3x^2+6x-9-16x^2+28x-20\qquad\text{combine like terms}\\\\=(3x^2-16x^2)+(6x+28x)+(-9-20)\\\\=-13x^2+34x-29\to\boxed{(2)}

4.\\p(x)=x^2-2x-24\\\\x^2-2x-24=0\\\\x^2+4x-6x-24=0\\\\x(x+4)-6(x+4)=0\\\\(x+4)(x-6)=0\iff x+4=0\ \vee\ x-6=0\\\\x=-4\ \vee\ x=6\to\boxed{(3)}

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Answer:

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Step-by-step explanation:

\text{Use}\\\\(ab)^n=a^nb^n\\\\(a^n)^m=a^{nm}\\\\a^{-n}=\dfrac{1}{a^n}\\-------------------\\\\2(5m^4n^{-1})^3=2(5)^3(m^4)^3(n^{-1})^3=2(125)m^{3\cdot4}n^{-1\cdot3}=250m^{12}n^{-3}=\dfrac{250m^{12}}{n^3}

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