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3 years ago

BRAINLIST AND 30 POINTS

Mathematics

1 answer:

svetlana [45]3 years ago

6 0

Answer:

1/16

Step-by-step explanation:

So if you want to divide an amount equally, you divide the numbers. In this scenario, what you would do is this:

1/2 needs to be split 8 times

(1/2)/8

If you have something like this where the numerator is a fraction, then you multiply 2x8. that gives you 16, so now you add the 1 on top and you get 1/16.

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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)= $f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........$

Where the terms in f prime $f^{1}$ (a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

$f^{1}$ (a)= $f^{1}$ (-4)=-8/( $-4)^{2}$

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+ $f^{1}(-4)(x+4)/1!+ f^{11}(-4)(x+4)^{2}/2!.............$

$=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+ 24/(-4)^{3} (-4)(x+4)^{2}/2!.............$

=-2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0

1 year ago

It takes 5 builders, 18 hours to build a wall.<br>How many minutes would it take 8 builders?

mr Goodwill [35]

It would take 135 minutes:)

7 0

3 years ago

Pls helphelpepelsjjejdkdkdjf

Yuki888 [10]

Answer:

bbb

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

X = y 2 - 1

pochemuha

Your answer would be option B. 2y² - y - 6 = 0. This is because if you were to substitute x = y² - 1 into the equation 2x - y = 4, you would get 2(y² - 1) - y = 4, which expands into 2y² - 2 - y = 4, and then simplifies to 2y² - y - 6 = 0.
I hope this helps!

7 0

3 years ago

Read 2 more answers

Simplified or solved for x ????

Leya [2.2K]

$\dfrac{16 \pm \sqrt{-32} }{2}$

$\dfrac{16 \pm \sqrt{-16 \times 2} }{2}$

$\dfrac{16 \pm 4i\sqrt{2} }{2}$

$8 \pm 2i \sqrt{2}$

5 0

3 years ago