Because I've gone ahead with trying to parameterize 
directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.
Rather than compute the surface integral over straight away, let's close off the hemisphere with the disk 
of radius 9 centered at the origin and coincident with the plane 
. Then by the divergence theorem, since the region 
is closed, we have
where 
is the interior of . 
has divergence
so the flux over the closed region is
The total flux over the closed surface is equal to the flux over its component surfaces, so we have
Parameterize by
with 
and 
. Take the normal vector to to be
Then the flux of across is
<span>the answer issssssssssss, 3713000</span>
Answer:
Line BD is Congruent to Line BD due to the Reflexive property. Angle Bad is congruent to angle BCD because of the third angle theorem therefore triangle ABD is congruent to triangle CBD because all angles and sides are congruent
I don't know if that will satisfy your teacher because some prefer different things but that leaves no ground to be inferred and explains everything word for word.
30 seconds, half a minute.
Answer:
y = 1
Step-by-step explanation:
Hello!
2x2=4 so 2 is the quotient and half of 2 is obviously 1. So you add y to that and its y = 1.
