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tresset_1 [31]
4 years ago
6

Find the next term in the sequence. 13, 15, 17, 19, ...

Mathematics
1 answer:
Lynna [10]4 years ago
6 0

Answer:

21

Step-by-step explanation:

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Kat is painting the edge of a triangular stage prop with reflective orange paint. The lengths of the edges of the triangle are (
Serggg [28]
Given:
edge 1 = 3x - 4
edge 2 = x² - 1
edge 3 = 2x² - 15

perimeter if x = 4

edge 1 = 3(4) - 4 = 12 - 4 = 8
edge 2 = 4² - 1 = 16 - 1 = 15
edge 3 = 2(4²) - 15 = 2(16) - 15 = 32 - 15 = 17

Perimeter = 8 + 15 + 17 = 40 feet.
7 0
3 years ago
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A student is constructing a pair of perpendicular lines using a compass and ruler. Here are her first steps:
Katyanochek1 [597]

The next step she should take is to use her ruler to join the given point to the point where the arcs intersect.

<h3>Steps in constructing perpendicular lines</h3>
  1. Place your compass on the given point
  2. Draw an arc across the line on each side of the given point. Do not adjust the compass width when drawing the second arc
  3. From each arc on the line, draw another arc on the opposite side of the line from the given point. The two new arcs will intersect.
  4. Use your ruler to join the given point to the point where the arcs intersect.
  5. Use your compass and ruler to draw a perpendicular line from each given point to the line segment

From this, we can deduce that her next step is to use her ruler to join the given point to the point where the arcs intersect

Thus, the next step she should take is to use her ruler to join the given point to the point where the arcs intersect.

Learn more about construction here:

brainly.com/question/27164219

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4 0
2 years ago
Equation for -10p+9p=12
Marizza181 [45]

p= -12 is your answer


5 0
3 years ago
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How can this be solved?
Molodets [167]
You might have to multiply or divide I just started learn g that stuff and I do t understand it still
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4 years ago
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What is the product of (3x^-4)(2y^-4)?
kap26 [50]

Answer:

6xy^-4

Step-by-step explanation:

we use the property

a^1×b^1=(ab)^1

4 0
3 years ago
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