In order to determine the expression that should be multiplied to n^2 to get 5n^3, divide 5n^3 by n^2. First for the numerical coefficient, 5 divide 1 is 5. For the variable n, n^3/n^2 is n. Thus, the term that should be multiplied to n^2 is 5n.
Answer:
Your annual expected value is -$550.
Step-by-step explanation:
0.002 probability that you will total your car.
If you total your car, you pay the insurance of $600, but you get the $25,000 insurance. So in total, the net value will be $24,400.
1-0.002 = 0.998 probability that you will not total your car.
In this case, you lose $600.
What is your annual expected value?
Multiply each net value by it's probability.
E = 0.002*24400 - 0.998*600 = -550
Your annual expected value is -$550.
Answer:
1 = 130° , 2 =50° , 3 = 85°, 4=45°
Step-by-step explanation:
1 =45 + 85 = 130 { sum of opposite interior angle equals exterior angle}
2 = 180 - 1 { angles on a straight line equals 180}
= 180 -130 = 50°
4 = 180 - 135 = 45° { angles on a straight line equals 180}
3 = 135 -2 { sum of opposite interior angles equals exterior angle; 3 + 2 = 135}
3 = 135-50 = 85°
Note : sum of opposite interior angles equals external exterior angle, let's prove it:
If we look at the triangle at the bottom left, we have :
85, 45 and r { let's denote r as the missing angle}
So 85 + 45 + r = 180° { sum of angles of a triangle}
By simple arithmetic
r = 180 - ( 85+45) = 180 - 130 = 50°
but r + 4 = 180° { sum of angles in a straight line equals 180°}
4 = 180 - 50 = 130°
So you see 4 is the exterior angle of the triangle opposite to 85° and 45° interior angles}
Step-by-step explanation:
$4 no toppings mentioned
1 . Consider lineups without x. You have to select
- 2 guards from 5 quards;
- 2 forwards from 3 forwards;
- 1 center from 4 centers.
It can be made in
different ways.
2. Consider lineups with x as guard. You have to select
- 2 guards from 6 quards (one of them must be x);
- 2 forwards from 3 forwards;
- 1 center from 4 centers.
It can be made in
different ways.
3. Consider lineups with x as forward. You have to select
- 2 guards from 5 quards;
- 2 forwards from 4 forwards (one of them must be x);
- 1 center from 4 centers.
It can be made in
different ways.
Therefore, the total number of different lineups is
120+60+120=300.