Let's call the event of the red die to show a six as event A, and the event of the green die to show a six as event B.
The theoretical probability is defined as the ratio of the number of favourable outcomes to the number of possible outcomes. On both dices, we have 6 possible outcomes(the numbers from 1 to 6), with one favourable outcome(the number 6), therefore, the probabilities of those events are:
Each roll is independent from each other, then, the probability of both events happening simultaneously is given by their product:
Using the additive rule of probability, we have the following equation for our problem:
the probability that the red die shows a six or the green die shows a six is 11/36.
Answer:
see below
Step-by-step explanation:
I do not know what the 'given expression' is, bu the three UN-highlighted expressions in each question 1 and 2 are equivalent
Only the highlighted one is not equiv to the other three
Answer: 1200 g pinapple
Step-by-step explanation:
800/2=400*3=1200
hope this helps
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
x=21−7y?
Step-by-step explanation:
I don't really know what else to do
