What is the answer to 3p^4 times 5p^2

Right triangle abc has one leg of length 6 cm, one leg of length 8 cm and a right angle at

Sauron [17]

Answer:
side length of the square = 10 cm

Explanation:
The attached image shows a diagram representing the scenario described in the problem.
Taking a look at this diagram, we can note that the side length of the square is equal to the hypotenuse of the right-angled triangle
Therefore, we can get the side of the square by calculating the length of the hypotenuse using Pythagorean theorem as follows:
(hypotenuse)² = (length of first leg)² + (length of second leg)²
(hypotenuse)² = (8)² + (6)²
(hypotenuse)² = 64 + 36
(hypotenuse)² = 100
hypotenuse = √100
hypotenuse = 10 cm

This means that the length of the side of the square is also 10 cm

Hope this helps :)

6 0

3 years ago

Solve for the value of n.<br> (9n-8)<br> (6n-7)

OverLord2011 [107]

Answer:

(9n-8)=(6n-7)

n = $\frac{1}{3}$

Step-by-step explanation:

Plug in if you want to check

3 0

3 years ago

PLEASE HELP ME PLEASE HELP ME OUT WITH THIS THANK YOU

Elza [17]

Answer:

is it just me or is the picture not loading

3 0

4 years ago

en una granja quieren poner una cerca con forma octogonal para guardar las ocas por las noches.Ya han colocado dos de los lados

ratelena [41]

Answer:

Perimeter = 32m

Area = 76.8m²

Step-by-step explanation:

Question:

On a farm they want to put an octagonal fence to keep the geese at night. They have already placed two of the sides and used 8 meters of fence. If we know that the apothem is 4.8 meters, what will be its perimeter? And your area?

Octagonal polygon is a polygon with 8sides.

Two sides of fence = 8m

One side of fence = 8/2 = 4m

Each sides = 4m

Apothem = 4.8m

Let's look at the steps that will enable us solve this question.

The area of a regular polygon is calculated as:

Area = ½ap

where a = the apothem of the polygon

p= the perimeter of the polygon.

Apothem is the distance between the centre of the polygon and the base of the polygon.

The perimeter (p) = The sum of all sides of the octagon

p = (4 + 4 + 4 + 4 + 4 + 4+ 4+ 4 )

p = 4(8)

perimeter (p) = 32m

Area = ½ ×a ×p = ½ × 4.8m × 32

Area = 153.6/2

Area = 76.8m²

3 0

3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

olga nikolaevna [1]

Answer:

maximum value , f max = 169 (taking the most out of the 4th power)

minimum value , f min = 169/3 (taking the least out of the 4th power)

Step-by-step explanation:

A) Since both function and restriction are symmetrical with respect to x,y and z, there is no reason for one to be more important than the others and therefore one solution would be x=y=z=λ and thus

x2 + y2 + z2 = 13 → 3λ² = 13 →λ² = 13/3

and f would be

f (x, y, z) = x4 + y4 + z4 = 3λ⁴ = 3*(13/3)²=13²/3=169/3

since x⁴ increases faster than 3*x² , f(x,y,z) would be a minimum

and the maximum value would be obtained taking the most out of x⁴, thus doing 2 coordinates =0 ( can be x=0 and y=0) and

z²= 13

f (x, y, z) = x4 + y4 + z4 = 13² = 169

B) strictly, using Lagrange multipliers

f (x, y, z) = x4 + y4 + z4

g (x, y, z) = x2 + y2 + z2 - 13

F(x,y,z) = f (x, y, z) -λ*g (x, y, z)

such that

Fx (x,y,z)= fx(x, y, z) -λ*gx (x, y, z) = 0 → 4*x³ - λ*2*x = 0 → 2*x*(2*x² -λ) = 0

thus x=0 or x²= λ/2

Fy (x,y,z)= fy(x, y, z) -λ*gy (x, y, z)= 0 → 4*y³ - λ*2*y = 0 → 2*y*(2*y² - λ) = 0

thus y=0 or y²= λ/2

Fz (x,y,z)= fz(x, y, z) -λ*gz (x, y, z)= 0 → 4*z³ - λ*2*z = 0→ 2*z*(2*z² - λ) = 0

thus z=0 or z²= λ/2

g (x, y, z) = 0 → x2 + y2 + z2 = 13 → 3*(λ/2) = 13 → λ=13*2/3

thus x²=y²=z²= λ/2 =13/3

f min = f (x, y, z) = x4 + y4 + z4 = 3*(13/3)²=169/3

for the x=0 , y=0 → z²= 13

f max = f (x, y, z) = x4 + y4 + z4 = 13² = 169

3 0

3 years ago