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Artemon [7]
1 year ago
7

angle EFG and angle GFH are a linear pair, angle EFG=2n + 25 and angle GFH=4n + 17 what are angles EFG and GFH?

Mathematics
1 answer:
Degger [83]1 year ago
7 0

The angles EFG and GFH are 71 and 109 degrees

<h3>How to determine the angles EFG and GFH?</h3>

The given parameters are:

EFG =2n + 25

GFH = 4n + 17

Linear pair angles are supplementary angles

So,we have

2n + 25 +4n + 17 = 180

Evaluate the like terms

6n= 138

Divide by 6

n = 23

Substitute n = 23 in EFG =2n + 25 and GFH = 4n + 17

EFG = 2 * 23 + 25 =71

GFH = 4 * 23 + 17 = 109

Hence, the angles EFG and GFH are 71 and 109 degrees


Read more about angles at:

brainly.com/question/25716982

#SPJ1

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Find the area of the irregular polygon. Round your answer to the nearest tenth if necessary.
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Find the perimeter and area of each figure.​
Sergio039 [100]

Answer:

  1. A = 2x; P = 4x+2. A = 4; P = 10.

  2. A = y² +2; P = 4y +2. A = 27; P = 22.

Step-by-step explanation:

1. The area is the sum of the marked areas of each of the tiles:

  A = x + x

  A = 2x

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The perimeter is the sum of the outside edge dimensions of the tiles. Working clockwise from the upper left corner, the sum of exposed edge lengths is ...

  P = 1 + (x-1) + x + 1 + (x+1) + x

  P = 4x +2

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When x=2, these values become ...

  A = 2·2 = 4 . . . . square units

  P = 4·2+2 = 10 . . . . units

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2. Again, the area is the sum of the marked areas:

  A = y² + 1 + 1

  A = y² +2

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The edge dimension of the square y² tile is presumed to be y, so the perimeter (starting from upper left) is ...

  P = y +(y-2) +1 +2 +(y+1) +y

  P = 4y +2

__

When y=5, these values become ...

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4 0
3 years ago
From a group of 3 men and 4 women, a delegation of 2 is selected. What is the expected number of men in the delegation?
Ostrovityanka [42]

Answer:

The expected number of men in the delegation is 0.86.

Step-by-step explanation:

Number of men = 3

Number of women = 4

A delegation of 2 is selected.

Let X be the number of men selected. So, the possible values of X are 0,1,2.

P(X=0)=\dfrac{^3C_0\times ^4C_2}{^7C_2}=\dfrac{2}{7}

P(X=1)=\dfrac{^3C_1\times ^4C_1}{^7C_2}=\dfrac{4}{7}

P(X=2)=\dfrac{^3C_2\times ^4C_0}{^7C_2}=\dfrac{1}{7}

The expected number of men in the delegation is

E(x)=0\times P(X=0)+1\times P(X=1)+2\times P(X=2)

E(x)=0\times \dfrac{2}{7}+1\times \dfrac{4}{7}+2\times \dfrac{1}{7}

E(x)=\dfrac{6}{7}

E(x)\approx 0.86

Therefore, the expected number of men in the delegation is 0.86.

4 0
3 years ago
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