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nlexa [21]
4 years ago
11

sal is making bracalets for a fundraser he uses 6 inches of yarn per bracalet how many bracalets can sal make with 5 ft of yarn

Mathematics
1 answer:
Iteru [2.4K]4 years ago
6 0

Answer:

10 bracelets

Step-by-step explanation:

we need to convert 5 ft to inches

1 ft = 12 inches

multiply by 5

5 ft = 60 inches

60 inches of yarn, 6 inches per bracelet

60/6 = 10

10 bracelets

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What is the slope of the line that passes through the points (8, -4)(8,−4) and (6, 2) ?(6,2)?
Nikitich [7]

Given:

The line passes through the points (8,-4) and (6,2).

To find:

The slope of the line.

Solution:

If a line passes though two points (x_1,y_1)\text{ and }(x_2,y_2), then the slope of the line is

m=\dfrac{y_2-y_1}{x_2-x_1}

The line passes through the points (8,-4) and (6,2). So, its slope is

m=\dfrac{2-(-4)}{6-8}

m=\dfrac{2+4}{-2}

m=\dfrac{6}{-2}

m=-3

Therefore, the slope of the line is -3.

5 0
3 years ago
Operations with rational expressions
Scorpion4ik [409]

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

Solution:

Given expression:

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}

To solve the given expression:

First simplify: \frac{50-2 w^{2}}{3 w^{2}+9 w-30}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30}=-\frac{2(w+5)(w-5)}{3(w-2)(w+5)}

Cancel the common factor (w + 5).

                      $=-\frac{2(w-5)}{3(w-2)}

Now substitute this in the given expression.

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{2(w-5)}{3(w-2)} \cdot \frac{w^{2}+5 w-14}{6 w-30}

Multiply the fractions \frac{a}{b} \cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{3(w-2)(6 w-30)}

Factor the denominator 3(w-2)(6 w-30) =18(w-2)(w-5)

                               $=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{18(w-2)(w-5)}                        

Cancel the common factor 2(w – 5).

                               $=-\frac{w^{2}+5 w-14}{9(w-2)}

Factor the numerator w^{2}+5 w-14=(w-2)(w+7)

                               $=-\frac{(w-2)(w+7)}{9(w-2)}

Cancel the common factor (w – 2).

                               $=-\frac{w+7}{9}

$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}

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murzikaleks [220]

Answer:

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6 0
3 years ago
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elena-14-01-66 [18.8K]
For this case what we should do is write correctly the given equation:
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The width of the laptop screen is:
 
D. W = 14.4 inch
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