Answer:
B. 12.5 feet below the surface of the water
Step-by-step explanation:
-20 + (-32.5) + 40
40 - 52.5
= -12.5 feet
= 12.5 feet below the water
Item 4 Find the median, first quartile, third quartile, and interquartile range of the data. 132,127,106,140,158,135,129,138 med
Ket [755]
Answer:
133.5, 127.5, 139.5, 12
Step-by-step explanation:
order data:
106, 127, 129, 132, 135, 138, 140, 158
Median:
The middle number: (8+1)/2 = 4.5 between the 4&5 numbers
= (135-132)/2= 1.5
1.5 + 132 = 133.5
lower quartile (1st quartile):
(8+1)/4 = 2.25 between the 2&3 numbers
(129+127)/4=0.5
0.5+127 = 127.5
upper quartile(3rd quartile):
(8+1)/4 x3 = 6.75 between the 6&7 numbers
(140-138)/4 x3 = 1.5
1.5 + 138 =139.5
Interquartile range:
139.5-127.5= 12
hope this helps
Answer: Rafi measured a summer camp and made a scale drawing. The scale he used was 1 millimeter = 3 meters. The sand volleyball court is 6 millimeters in the drawing.
Step-by-step explanation:
Answer:
Below are the responses to the given question:
Step-by-step explanation:
Let X become the random marble variable & g have been any function.
Now.
For point a:
When X is discreet, the g(X) expectation is defined as follows
Then there will be a change of position.
E[g(X)] = X x∈X g(x)f(x)
If f is X and X's mass likelihood function support X.
For point b:
When X is continuing the g(X) expectations is calculated as, E[g(X)] = Z ∞ −∞ g(x)f(x) dx, where f is the X transportation distances of probability.If E(X) = −∞ or E(X) = ∞ (i.e., E(|X|) = ∞), they say it has nothing to expect from EX is occasionally written to stress that a specific probability distribution X is expected.Its expectation is given in the form of,E[g(X)] = Z x −∞ g(x) dF(x). , sometimes for the continuous random vary (x). Here F(x) is X's distributed feature. The anticipation operator bears the lineage of comprehensive & integral features. The superposition principle shows in detail how expectation maintains equality and is a skill.
