Question

What is the slope of the line that passes through the points (8,-8) and (5,-1)?

Answer 1

Hey there!

• Answer :

$\sf{ \purple{ \boxed{\bold{m = - \dfrac{7}{3} }}}}$

• Explanation :

We are given the points $\sf{P_1(\overbrace{ \blue{8}}^{\blue{x_1}} ,\underbrace{\orange{-8}}_{ \orange{y_1}}) \: and \: P_2(\overbrace{ \green{5}}^{\green{x_2}} ,\underbrace{\red{-1}}_{\red{y_2} })}$ . To find the slope $\sf{\purple{m}}$ of such a line, we use the slope formula which is the following:

$\sf{ \purple{m} }= \dfrac{\Delta y}{\Delta x} = \dfrac{ \red{y_2} - \orange{y_1}}{ \green{x_2 }- \blue{x_1}}$

⇢Now, by plugging in our values, we get :

$\sf{ \purple{m}} = \dfrac{ \red{ - 1} - \orange{( - 8)}}{ \green{5} \: - \: \blue{8}} = \dfrac{ \: \: 7 \: }{ - 3 \: } \\ \\ \implies \sf{ \purple{ \boxed{m = - \dfrac{7}{3} }}}$

Therefore, the slope of the line is $\sf{ \purple{ \boxed{m = - \dfrac{7}{3} }}}$

Answer 2

SOLVING

$\Large\maltese\underline{\textsf{A. What is Asked}}$

What is the slope of a linear function that goes through (8,-8) and (5,-1)?

$\Large\maltese\underline{\textsf{B. This problem has been solved!}}$

Formula utilised, here $\bf{\dfrac{y2-y1}{x2-x1}}$.

We utilise that formula because we have two points as our given information.

So, we

put in the values

$\bf{\dfrac{-1-(-8)}{5-8}}$ | subtract on top and bottom

$\bf{\dfrac{-1+8}{-3}}$ | simplify

$\bf{\dfrac{7}{-3}$

$\cline{1-2}$

$\bf{Result:}$

                $\bf{=Slope=-\dfrac{7}{3}}$

$\LARGE\boxed{\bf{aesthetic\not1\theta l}}$